Does this series converge or diverge? (alternating series test)
\[\sum_{n=1}^{\infty}\frac{ (-1)^{n+1} }{ 7n^8 +2 }\]
Well, you don't even need an alternating series test for this series, well, unless you asked to use precisely this test.
Alternating Series Test: Suppose you have a series in a form. \(\color{#000000}{ \displaystyle \sum_{ n=k }^{ \infty } (-1)^nA_n}\) or \(\color{#000000}{ \displaystyle \sum_{ n=k }^{ \infty } (-1)^{n-1}A_n}\). (which either one of these is same in terms of convergence) If \(A_n\) is (an always positive and) a monotonically decreasing sequence, meaning that: \(\color{#000000}{ \displaystyle A_{n+1} <A_n}\) for all \(n\), THEN the series converges.
For example: \(\color{#000000}{ \displaystyle \sum_{ n=3 }^{ \infty }(-1)^n\frac{1}{n}\quad \Longrightarrow~~ {\rm converges.}}\) Because the series alternates and the non-alternating part (1/n) in this case, always decreases, the series will converge.
You can re-write the series in your case as, \(\color{#000000}{ \displaystyle \sum_{ n=0 }^{ \infty }(-1)^{n+1}\frac{1}{7n^8+2}}\)
The series is alternating, and the non-alternating part is always decreasing (because the denominator gets larger and larger causing the term to get smaller and smaller).
|dw:1462404031826:dw|
Join our real-time social learning platform and learn together with your friends!