What is the area of a sector with a central angle of 160 degrees and a diameter of 5.8 m? Round the answer to the nearest tenth.
\[\frac{\text{ Area of sector }}{\text{ Area of circle }}=\frac{\text{central angle }}{ 360^\circ }\]
solve for Area of sector remember area of a circle (you know the full circle ) is pi*r^2
\[\frac{\text{ Area of sector }}{\pi r^2}=\frac{\text{central angle }}{ 360^\circ }\]
multiply both sides by pi*r^2 to get the formula for area of sector
\[\text{ Area of sector }= \pi r^2 \cdot \frac{\text{ central angle}}{360^\circ}\]
this formula is when the central angle is in degrees
which it is here
pi*r^2 should be 8.41*pi not just 8.41
\[360x = 1345.6\pi\] ?
which did you multiply both sides by 360
you are trying to solve for x not 360x :p
\[x=\frac{1345.6 \pi}{360}\]
why did you multiply both sides by 360 *
I was writing down, like, the v first step of the equation. I tend to take things in baby steps, hah
Hm... I think I got it wrong somewhere cause 3.7 isn't exactly a viable answer
Hang on
yea 3.7 isn't correct
looks like you keep ignoring the pi in your calculations
Whoops
did you get your answer yet?
use 3.14 for pi you have 3.73 * 3.14 is the last thing you should have now
i'm sorry i must go
Oh, alright! I'll try and work it out from here.
Got it! 11.7 m^2
Join our real-time social learning platform and learn together with your friends!