Question

http://prntscr.com/b0sw1h

Answer 1

This is what I'm picturing but I'm not sure

Answer 2

@jim_thompson5910

Answer 3

see attached

Answer 4

So I just do the typical 1/2bh?
@jim_thompson5910

Answer 5

no I posted the formula you'll use

area = (1/2)*b*c*sin(A)

b = 1.32
c = 2.75
A = 35 degrees

Answer 6

1/2*b*h is only used if you know the base and height. We can find the base easily, but the height is unknown

Answer 7

http://www.mathopenref.com/triangleareasas.html

Answer 8

that page has an interactive diagram to play with, an explanation where the formula comes from, and a special calculator designed just for this type of problem

I don't recommend using the special calculator as your first step. Use that as your last step so you can check your answer

Answer 9

I'm a bit confused. Are b and c the known sides while A is the angle in this case?

Answer 10

yes. Do you see how I set up the drawing in the attachment?

Answer 11

Yep

Answer 12

draw any triangle ABC

'a' is opposite angle A
'b' is opposite angle B
'c' is opposite angle C

I let b & c be the two known sides. So that means A is the known angle

Answer 13

2.08 is the answer : )

Answer 14

I mean is it? If not, why?
@jim_thompson5910

Answer 15

no it's not

Answer 16

\[\Large \text{Area} = \frac{1}{2}*b*c*\sin(A)\]
\[\Large \text{Area} = \frac{1}{2}*1.32*2.75*\sin(35^{\circ})\]
\[\Large \text{Area} = ??\]

Answer 17

Ah, I forgot to half it.

1.04 right?

Answer 18

yes

(1/2)*1.32*2.75*sin(35) = 1.04104123197714