Question

http://prntscr.com/b187s6

Answer 1

I just need help with C and D

Answer 2

@ParthKohli

Answer 3

ok jsust find exact, i don't care at this point I'm p

Answer 4

panicking

Answer 5

OK, cool. The problem is just about solving quadratic equations.

Answer 6

Do you have to use those values given in part A for part C, D as well?

Answer 7

Because then it means that \(s = 100\) and \(v = 60\) so your function looks like\[H(t) = -16t^2 + 60t + 100\]

Answer 8

I have no idea

Answer 9

i was doing fine on the last question

Answer 10

He already did part A for you lol

Answer 11

Now \[H(t) = g(t)\]\[\Rightarrow -16t^2 +60t+100 = 20+38.7t\]\[\Rightarrow -16t^2 + (60-38.7)t + 80=0\]\[\Rightarrow -16t^2 + 21.3t + 80 = 0\]aaand there it is... the quadratic equation.

Answer 12

I already did A and B

Answer 13

wait a sec, parth, doesnt it say we have to make a table

Answer 14

"ok jsust find exact, i don't care at this point I'm p"
- ILovePuppiesLol

Answer 15

C
Using a table, I find that g(t)=H(t) at approximately (2, 138)
This solution represents where and when the two objects will be at the same height. On a graph, this would be where the two lines intersect.
I double checked this by using my graphing calculator to calculate where they intersect. It gave me (2.0058915, 137.97588)

D
When the two objects intersect, the projectile is going up. I know because the maximum height that the projectile will reach is 138.25. This number is higher than the point of intersection, meaning that the projectile has yet to begin falling.

Answer 16

http://openstudy.com/updates/53447b09e4b02bb88e6590e9

Answer 17

that is the source someone already asked this question they just had different numbers you just need to change calculations on the numbers they had from A to D but it is the same exact thing

Answer 18

I'm just gonna wing it and hope for the best, thanks guys