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Mathematics 9 Online
rebeccaxhawaii (rebeccaxhawaii):

@mathmale HALP

rebeccaxhawaii (rebeccaxhawaii):

rebeccaxhawaii (rebeccaxhawaii):

rebeccaxhawaii (rebeccaxhawaii):

#3

OpenStudy (mathmale):

Got to hand it to you: You're spunky, fast, determined, motivated.

rebeccaxhawaii (rebeccaxhawaii):

freshman/ healthy foods.

rebeccaxhawaii (rebeccaxhawaii):

hehehehe thanks

OpenStudy (mathmale):

Can you explain in words what P(A|B) means? What P(B|A) means?

rebeccaxhawaii (rebeccaxhawaii):

the probability of A given B

rebeccaxhawaii (rebeccaxhawaii):

right?

OpenStudy (mathmale):

Yes. Another way to explain it: Given that Event B has occurred, what is the probability that A will occur?

OpenStudy (mathmale):

so, assuming you have created an actual table with numbers in it, with totals of rows and totals of columns, we now focus on any 1 row and any 1 column (your choice of each).

OpenStudy (mathmale):

How are your rows labeled? your columns?

rebeccaxhawaii (rebeccaxhawaii):

P(healthy foods|freshman) and P(freshman\healthy foods) right?

OpenStudy (mathmale):

(thinking)

OpenStudy (mathmale):

Given that a student selected at random from among your 20 (or more) subjects is a freshman, what is the probability that he or she selects healthy foods? How would you calc. that?

rebeccaxhawaii (rebeccaxhawaii):

is what i wrote correct?

OpenStudy (mathmale):

First, you'd need to know, from your table, how many of your subjects are freshmen.

OpenStudy (mathmale):

What you have written is correct as far as it stands. I assume you also have rows for sophs and jrs. but really, for what you are doing RIGHT now, heck with the sophs and jrs.

OpenStudy (mathmale):

So, how many of your sweet subjects are frosh?

rebeccaxhawaii (rebeccaxhawaii):

no i did not include them. making this as painless as possible.

rebeccaxhawaii (rebeccaxhawaii):

241 of them

OpenStudy (mathmale):

uh-oh. But anyway. how many frosh?

rebeccaxhawaii (rebeccaxhawaii):

241

OpenStudy (mathmale):

Wow, what a big study. Req'd to use at least 20 subjects, but reb rebels and uses 241 for frosh alone. Wow.

rebeccaxhawaii (rebeccaxhawaii):

over achiever c;

OpenStudy (mathmale):

And, of those 241, how many eat primarily healthy foods?

rebeccaxhawaii (rebeccaxhawaii):

191 of them

OpenStudy (mathmale):

So your conditional prob, the prob that GIVEN that your selected student is a frosh, he or she eats primarily healthy foods, is P(A|B). How would you calculate this, using the 191 and 241 data ?

rebeccaxhawaii (rebeccaxhawaii):

191/214

OpenStudy (mathmale):

Perfect. Just perfect.

rebeccaxhawaii (rebeccaxhawaii):

WAIT

OpenStudy (mathmale):

But now we have to reverse the order: We need to calc P(B|A). In other woerds,

rebeccaxhawaii (rebeccaxhawaii):

NO

rebeccaxhawaii (rebeccaxhawaii):

ITS 50/241

OpenStudy (mathmale):

given that the sweetie student you've picked eats healthy foods primarily, what is the P that that sweetie is a frosh?

rebeccaxhawaii (rebeccaxhawaii):

0.20746887966

OpenStudy (mathmale):

Without a completely filled in table, how can you answer that?

OpenStudy (mathmale):

Hold, hold. Where are we? NO what?

OpenStudy (mathmale):

You said there were 241 frosh, and that 191 of them claimed to eat only healthy foods. P(healthy food | frosh) = 191/241.

rebeccaxhawaii (rebeccaxhawaii):

no 50 of them i was looking at the ones that eat unhealthy so its 50/214

rebeccaxhawaii (rebeccaxhawaii):

214/50 = p(freshy | healthy foods)

OpenStudy (mathmale):

It's not 214/50. No probability can be smaller than 0 nor greater than 1. Try again on that one.

rebeccaxhawaii (rebeccaxhawaii):

P(B|A) im confused on what i would be plugging in because P(A|B) is 50/241

OpenStudy (mathmale):

First, are you sat. with our previous result, 191/241?

rebeccaxhawaii (rebeccaxhawaii):

http://prntscr.com/b1jzpg

rebeccaxhawaii (rebeccaxhawaii):

that is for unhealthy foods

OpenStudy (mathmale):

I'm sorry, R, but I'm losing track of where we are and what you want to know. Please provide some more structure here.

rebeccaxhawaii (rebeccaxhawaii):

we are doing question #3 here is the chart that i have made http://prntscr.com/b1jzpg I chose row healthy foods and column freshman so far i have P(A|B)=50/241 now i have to find P(B|A)

OpenStudy (mathmale):

Our communication seems to have broken down over the issue "214/50 = p(freshy | healthy foods)" No probability can be less than 0 or greater than 1; 214/50 is 4.28.

OpenStudy (mathmale):

All right. How many students, total, eat healthy foods?

rebeccaxhawaii (rebeccaxhawaii):

111

OpenStudy (mathmale):

yes, I have the table in fron t of me, but I'd like to hear it from you. OK, 111 students, total. Now, how many of those 111 students are freshmen?

rebeccaxhawaii (rebeccaxhawaii):

50

OpenStudy (mathmale):

Right. So the condit. prob. is 50/111.

rebeccaxhawaii (rebeccaxhawaii):

so thats P(B|A)?

OpenStudy (mathmale):

Let me put it this way: It's the probability P(student is a freshman | student eats healthy foods).

OpenStudy (mathmale):

Given that the student chosen at random eats healthy foods, what is the prob. tht that same student is a frosh? Answer: 50/111.

OpenStudy (mathmale):

As explained in a PM some time ago, I'd like to get off the 'Net very, very soon. Is it possible that we could meet again on O. S. tomorrow to finish this discussion?

rebeccaxhawaii (rebeccaxhawaii):

no can do. its due today. *CRIES*

rebeccaxhawaii (rebeccaxhawaii):

but ill let you go, thanks for the help.

OpenStudy (mathmale):

can you do #4?

rebeccaxhawaii (rebeccaxhawaii):

yes im fine with #4 just #3 is being a pain

OpenStudy (mathmale):

We went over that briefly some time ago. There are a total of 400 something students. How many of these students satisfy 2 criteria at once: frosh and healthy (or whatever)?

OpenStudy (mathmale):

Weren't we fionished with #3?

OpenStudy (mathmale):

If not, what specifically do you still need help with in #3?

OpenStudy (mathmale):

If you choose A=frosh and B=healthy foods, we MUST stick with those definitions throughout Problem #3.

rebeccaxhawaii (rebeccaxhawaii):

can you tell me in words what P(A|B) and P(B|A) is we have got P(A|B)=50/241 and P(B|A)=50/111 but im lost

OpenStudy (mathmale):

Pls verify the meaning of A and B first. A= the event that .... B= the event that ... "

rebeccaxhawaii (rebeccaxhawaii):

hmm. no clue.

OpenStudy (mathmale):

If the orig. problem statement doesn't specify that (and I don't think it did), then it's entirely up to you to define A and B according to the situation you designed (healthy foods)

rebeccaxhawaii (rebeccaxhawaii):

a is healthy goods and b is total for freshman

OpenStudy (mathmale):

I'd rather that B: student chosen at random happens to be a freshman, and A: student chosen at random happens to eat healthy foods

OpenStudy (mathmale):

What is P(A|B)? This says we already know that the randomly chosen student is a frosh. Fine. how many frosh have we, total?

rebeccaxhawaii (rebeccaxhawaii):

okay but how are P(A|B) and P(B|A) different?

rebeccaxhawaii (rebeccaxhawaii):

why do we plug in different events for both.

OpenStudy (mathmale):

gott a finish P(a|B) first. Pls hold that question; i'm not avoiding it, just want to finish one thing at a time.

rebeccaxhawaii (rebeccaxhawaii):

yes sir. okay so we have 214 total fresh

OpenStudy (mathmale):

P(student eats healthy | student is a frosh) = ? how many of the 486 students are frosh? 214. Of those 214, how many eat healthy?

rebeccaxhawaii (rebeccaxhawaii):

241 sorry. 50 of them each healthy

OpenStudy (mathmale):

Nothing to be sorry about. 241 students total, of whom 50 eat healthy. P(A|B)=50/241. Done. P(B|A)=? same as P(student is a frosh | student eats healthy)

OpenStudy (mathmale):

How many students of both class levels eat healthy?

rebeccaxhawaii (rebeccaxhawaii):

111

OpenStudy (mathmale):

Of those 111 students, how many are frosh?

rebeccaxhawaii (rebeccaxhawaii):

50

OpenStudy (mathmale):

then P(B|A) = 50/111.

OpenStudy (mathmale):

Notice that this is NOT the same as P(A|B). We were exploring, hopefully without any predefined conclusion that the two probabilities were the same.

rebeccaxhawaii (rebeccaxhawaii):

so thats all it was? WHYYY DO I OVER COMPLICATE EVERYTHING?

rebeccaxhawaii (rebeccaxhawaii):

ugh. thank you for all your patience with me being so slow.

OpenStudy (mathmale):

Prob (especially) and stat were originally very, very hard for me. You're not slow! Glad to have gotten to know you better and to have achieved some productive results on your questions! Good night.

rebeccaxhawaii (rebeccaxhawaii):

good night c: and thanks again

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