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OpenStudy (samigupta8):
Four points with position vectors a,b,c and d are coplanar such that
(sinalpha) a +(2sin2beta)b+(3sin3gamma)c-d=0 .Then,the least value of expression sin^2alpha+sin^2(2beta)+sin^2(3gamma) is
OpenStudy (astrophysics):
Use latex
OpenStudy (astrophysics):
Four points with position vectors a,b,c and d are coplanar such that
\[( \sin \alpha) \vec a+(2 \sin^2 \beta) \vec b+(3 \sin^3 \gamma) \vec c - \vec d = 0\]. Then, the least value of expression \[\sin^2\alpha+\sin^2(2\beta)+\sin^2(3\gamma) \] is
OpenStudy (samigupta8):
Btw, the second term and third term you wrote were not correct.
Those were 2sin2beta and 3sin3gamma
OpenStudy (samigupta8):
@astrophysics can you help please?
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OpenStudy (samigupta8):
@ganeshie8 sir can you help please?
OpenStudy (samigupta8):
In this question can you please explain this?
sina+2sin2b+3sin3c=1 .
How is it derived?
ganeshie8 (ganeshie8):
I have no idea sorry :(
ganeshie8 (ganeshie8):
@Kainui
OpenStudy (samigupta8):
Okay!
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