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Mathematics 15 Online
OpenStudy (samigupta8):

Vectors!

OpenStudy (samigupta8):

Four points with position vectors a,b,c and d are coplanar such that (sinalpha) a +(2sin2beta)b+(3sin3gamma)c-d=0 .Then,the least value of expression sin^2alpha+sin^2(2beta)+sin^2(3gamma) is

OpenStudy (astrophysics):

Use latex

OpenStudy (astrophysics):

Four points with position vectors a,b,c and d are coplanar such that \[( \sin \alpha) \vec a+(2 \sin^2 \beta) \vec b+(3 \sin^3 \gamma) \vec c - \vec d = 0\]. Then, the least value of expression \[\sin^2\alpha+\sin^2(2\beta)+\sin^2(3\gamma) \] is

OpenStudy (samigupta8):

Btw, the second term and third term you wrote were not correct. Those were 2sin2beta and 3sin3gamma

OpenStudy (samigupta8):

@astrophysics can you help please?

OpenStudy (samigupta8):

@ganeshie8 sir can you help please?

OpenStudy (samigupta8):

In this question can you please explain this? sina+2sin2b+3sin3c=1 . How is it derived?

ganeshie8 (ganeshie8):

I have no idea sorry :(

ganeshie8 (ganeshie8):

@Kainui

OpenStudy (samigupta8):

Okay!

OpenStudy (samigupta8):

No problem..

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