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Mathematics 17 Online
OpenStudy (first_world_problems):

1/4=8^3x^+5

sam (.sam.):

Could you rewrite that, I don't understand what you've written

OpenStudy (first_world_problems):

it s 1/4 = 8 with exponents of 3x plus 5

OpenStudy (first_world_problems):

@.Sam.

OpenStudy (first_world_problems):

1/4=8^3x+^5

OpenStudy (first_world_problems):

i need my answer to bee in a fraction

OpenStudy (sachintha):

Let me re-write it :) \(\frac{1}{4}=8^{(3x+5)}\)

OpenStudy (first_world_problems):

yes

OpenStudy (first_world_problems):

how did you do that

OpenStudy (sachintha):

It's latex.

OpenStudy (jjcoolja12):

Let's solve your equation step-by-step. 1 4 =(83)(x5) 1 4 =512x5 Step 1: Subtract 512x^5 from both sides. 1 4 −512x5=512x5−512x5 −512x5+ 1 4 =0 Step 2: Subtract 1/4 from both sides. −512x5+ 1 4 − 1 4 =0− 1 4 −512x5= −1 4 Step 3: Divide both sides by -512. −512x5 −512 = −1 4 −512 x5= 1 2048 Step 4: Take root. x=( 1 2048 )( 1 5 ) x=0.217638 Answer: x=0.217638 http://www.mathpapa.com/algebra-calculator.html i got bored watching you guys

OpenStudy (sachintha):

xD nice one @jjcoolja12

OpenStudy (first_world_problems):

no it needs to be fraction that's all the answer choices i have are

sam (.sam.):

Now that is confusing hahah

OpenStudy (first_world_problems):

yawn

sam (.sam.):

What's your attempt on this @First_world_PROBLEMS ?

OpenStudy (jjcoolja12):

OpenStudy (first_world_problems):

a.-7/3 b. -13/9 c.-17/9 d.-7/9

OpenStudy (first_world_problems):

those are the answer choices i have for this problem

OpenStudy (first_world_problems):

a fail @.Sam. thats what is was

OpenStudy (first_world_problems):

kept getting syntax error

OpenStudy (sachintha):

Do you know how to rewrite it in logarithmic form?

sam (.sam.):

Actually

OpenStudy (jadedry):

1/4 = \[\frac{ 1 }{ 2^2 } = 2^{-2}\] 8 = \[2^3\] so you can convert your original equation to: where: \[2^{3 * (3x +5)}\] can you solve it now?

OpenStudy (sachintha):

You also have to use the base change formula.

OpenStudy (first_world_problems):

@sleepyjess can you help me peeeeaasse theses guys are no help i neeeed a fraction answer not a decimal

OpenStudy (sachintha):

Jadedry's method is much more easier.

OpenStudy (jadedry):

To recap: \[2^{-2} = 2^{3 * (3x +5)} = 2^{9x + 15}\]

sam (.sam.):

There's an easy way to solve this kinda like @Jadedry did, just 5 steps

OpenStudy (sachintha):

@First_world_PROBLEMS Try to follow the steps and get the answer. You won't be able to solve these types of equations if you want the answer straight forward.

OpenStudy (jadedry):

^ what he said

OpenStudy (jadedry):

it's very important to understand the question and the path to the answer!

OpenStudy (first_world_problems):

right now im low on time i've been working on this last problem for almost an hour wich is rediculous

OpenStudy (first_world_problems):

which*

OpenStudy (sachintha):

It's -1.88.. :3

OpenStudy (sachintha):

@Jadedry Show him the steps to calculate :)

OpenStudy (first_world_problems):

no thanks

OpenStudy (jadedry):

Well, you just to solve for x now. You can just take them as linear equations rather than indices, just calculate: \[-2 = 9x + 15\]

OpenStudy (first_world_problems):

x.x

OpenStudy (first_world_problems):

rip here lies First_world_PROBLEMS

OpenStudy (phi):

can you solve -2 = 9x+15 ?

OpenStudy (first_world_problems):

No -_-'

OpenStudy (first_world_problems):

14=8^(3x+5)

OpenStudy (first_world_problems):

just over it

OpenStudy (jadedry):

What about: \[-17 = 9x\] solve for x!

OpenStudy (first_world_problems):

irrelevant ^

OpenStudy (sachintha):

Ohh man, you will have to recap your previous knowledge @First_world_PROBLEMS.

OpenStudy (first_world_problems):

kidding

OpenStudy (first_world_problems):

this problem has been closed

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