Question

Three-d..

Answer 1

what???

Answer 2

x-ysina-zsinb=0
xsina-y+zsinc=0
xsinb+ysinc-z=0 be three planes such that a+b+c=π/2
Then the planes
1).intersect in a point
2).intersect in a line
3).mutually perpendicular and intersect in a point.

Answer 3

you should get something by solving the 3 equations together and substituting for a+b+c as pi/2

Answer 4

start by finding the normal vectors of each of the given planes

Answer 5

they are staring at your face, what are they ?

Answer 6

1). 1,-sina,-sinb
2).sina,-1,sinc
3).sinb,sinc,-1

Answer 7

@ganeshie8

Answer 8

I have tried this and couldn't find the answer.
Maybe try taking the dot product of pairs of normal vectors to see if they are perpendicular

Answer 9

Keep in mind that if the normal vectors are perpendicular, then the planes will also be perpendicular

Answer 10

Sir, when i took the dot products it came out to be
2sina=sinbsinc
2sinb=sinasinc
2sinc=sinasinb