Question

yay math

Answer 1

Carl conducted an experiment to determine if there is a difference in the mean body temperature between men and women. He found that the mean body temperature for a sample of 100 men was 91.1 with a population standard deviation of 0.52 and the mean body temperature for a sample of 100 women was 97.6 with a population standard deviation of 0.45.

Assuming the population of body temperatures for men and women is normally distributed, calculate the 98% confidence interval and the margin of error for the mean body temperature for both men and women. Using complete sentences, explain what these confidence intervals mean in the context of the problem.

Answer 2

(:

Answer 3

@agent0smith

Answer 4

Algebra 2?

Answer 5

ARE YOU GOOD IN MATH CAUSE I NEED HELP @rebeccaxhawaii

Answer 6

These are confidence intervals right

Answer 7

correct

Answer 8

We did one of these last night

Answer 9

2.33?

Answer 10

I think your right z = 2.33

Answer 11

for 98% \[\large mean \pm 2.33*\frac{ s.d. }{ n }\]sd is st deviation, n is number of people in sample

Answer 12

why would 96%=1.96 and 98%=2.33

Answer 13

because z scores.

Answer 14

oh duh. thanks. okay wait.

Answer 15

http://image.slidesharecdn.com/confidenceintervalsandthet-distribution-091125151459-phpapp02/95/confidence-intervals-and-the-t-distribution-4-728.jpg?cb=1259162120

Answer 16

so we do it for both the females and males

Answer 17

whats the difference betweenand