math is so fun..

Question

math is so fun..

rebeccaxhawaii · Answer

Carl conducted an experiment to determine if there is a difference in the mean body temperature between men and women. He found that the mean body temperature for a sample of 100 men was 91.1 with a population standard deviation of 0.52 and the mean body temperature for a sample of 100 women was 97.6 with a population standard deviation of 0.45.

Assuming the population of body temperatures for men and women is normally distributed, calculate the 98% confidence interval and the margin of error for the mean body temperature for both men and women. Using complete sentences, explain what these confidence intervals mean in the context of the problem

rebeccaxhawaii · Answer

For this problem they have provided the mean and standard deviation aka sd. Therefore we would use the formula `z*sigma /sqrtn `
 
By looking at our z chart we see that 98%= the sd of 2.33
 
Females:   `z*sigma /sqrtn=2.33*0.45 /sqrt100=0.10485 `
therefore `97.6+-0.10485 `, which is `96.59515 and 97.70485 `

Males :`z*sigma /sqrtn=2.33*0.52 /sqrt100=0.12116 `
therefore `91.1+-0.12116 ` which is `90.97884 and 9.22116 `

rebeccaxhawaii · Answer

thats what i got. but lemme screenshot

rebeccaxhawaii · Answer

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