How does this model demonstrate the Pythagorean Theorem?
A. The sum of the lengths of the shortest and the longest sides is equal to twice the length of the middle side. So double the length of the longer leg of any right triangle is equal to the sum of the shorter leg and the hypotenuse. B. The sum of the area of the two smaller squares is equal to the area of the larger square. So the sum of the lengths of the two legs of any right triangle squared is equal to the length of the hypotenuse squared. C. The sum of the area of the smallest and the largest squares is equal to the area of the middle square. So the sum of the lengths of the shorter leg and the hypotenuse of any right triangle squared is equal to the length of the middle leg squared. D. The length of the longest side minus two equals the length of the middle side. The length of the middle side minus two equals the length of the shortest side. So the length of the short leg of any right triangle is equal to the length of the middle leg minus 2, and the length of the hypotenuse is equal to the length of the middle leg plus 2.
tl;dr the words but those boxes mean 8^2 6^2 and 10^2 and stuff and 6^2 + 8^2 = 10^2
If you add the two small square things you get the big square thing
so C
No, not C. In fact no answer is correct because the one they mean to be the answer is poorly worded and incorrect.
A
Yeah for real @mathstudent55 just read it and they were totally wrong lol
When they wrote the question I mean
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