Question

What is the value of 373 using the identity (x − y)3 = x3 − 3x2y + 3xy2 − y3?

Hint: 373 = (40 − 3)3; therefore, x = 40 and y = 3.

Answer 1

Overally plugging in the x and y equaling :

37^3=(40-3)^3=40^3-3*40^2*3+3*40*3^2-3^3=

Answer 2

I do not know what it would equal overall :(

Answer 3

@Mehek14

Answer 4

Identity (x − y)^3 = x^3 − 3x^2y + 3xy^2 − y^3

373 = (40 − 3)^3


Replace x by 40 and y by 3

37^3 = (40 − 3)^3 = x^3 − 3x^2y + 3xy^2 − y^3

Answer 5

37^3 =

(40 − 3)^3 = 40^3 − 3*40^2 *3 + 3*40 * 3^2 − 3^3

Crank out this: 40^3 − 3*40^2 *3 + 3*40 * 3^2 − 3^3

Answer 6

40^3 =

− 3*40^2 *3 =

+ 3*40 * 3^2 =

− 3^3 =

Get the numerical value of each term and then add those.

Answer 7

i got -6947 @Directrix

Answer 8

Im not sure if that seems correct, however I just may be over thinking

Answer 9

@pooja195

Answer 10

Let me see what I get.

Answer 11

40^3 = 64 000

− 3*40^2 *3 = -14 400

3*40 * 3^2 = 1 080

− 3^3 = - 27

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We have to add all this.

Answer 12

>>i got -6947

I did not get that.

Answer 13

I got that as well lol

Answer 14

I got this after I added the four parts:

50 653

Answer 15

If this is a "show your work" problem, you'll need to include all of the calculations from the expansion in your work.

Answer 16

oh.... i added them and got the -6947, let me try again

Answer 17

I am still adding them and getting my answer... @Directrix

Answer 18

Add two at the time. Then, add that sum to the next one.

Answer 19

I think you may be missing this one: 40^3 = 64 000