If an object is dropped from a height of 126 feet, the function h(t) = –16t2 + 126 gives the height of the object after t seconds. Approximately when will the object hit the ground? Round to the nearest hundredth.
I know the answer is 2.81 but, how do I do the work to find the problem that gives me that answer???
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Vocaloid (vocaloid):
set the equation equal to 0 (since h = 0 when it's on the ground)
Vocaloid (vocaloid):
0 = –16t2 + 126
know where to go from there?
OpenStudy (anime_lover_levi):
So turn the T into a 0?
(Btw gakupo , kaito and len/rin are my fav XD)
Vocaloid (vocaloid):
no, you're solving FOR t
Vocaloid (vocaloid):
start by subtracting 126 from each side
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OpenStudy (anime_lover_levi):
ok
Vocaloid (vocaloid):
-126 = -16t^2
Vocaloid (vocaloid):
divide both sides by 16
Vocaloid (vocaloid):
7.875 = t^2
Vocaloid (vocaloid):
then solve for t
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OpenStudy (anime_lover_levi):
then.....hmm... sorry I'm bad at math so I'm trying to prossess
Vocaloid (vocaloid):
to solve
7.875 = t^2
take the square root of both sides
Vocaloid (vocaloid):
sqrt(7.875) = 2.81 which matches your answer
Vocaloid (vocaloid):
let me know if you need me to explain a certain step
OpenStudy (anime_lover_levi):
i will I'm just reading back and making sure ig to it, math is like y worst subject
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