If an object is dropped from a height of 126 feet, the function h(t) = –16t2 + 126 gives the height of the object after t seconds. Approximately when will the object hit the ground? Round to the nearest hundredth. I know the answer is 2.81 but, how do I do the work to find the problem that gives me that answer???
set the equation equal to 0 (since h = 0 when it's on the ground)
0 = –16t2 + 126 know where to go from there?
So turn the T into a 0? (Btw gakupo , kaito and len/rin are my fav XD)
no, you're solving FOR t
start by subtracting 126 from each side
ok
-126 = -16t^2
divide both sides by 16
7.875 = t^2
then solve for t
then.....hmm... sorry I'm bad at math so I'm trying to prossess
to solve 7.875 = t^2 take the square root of both sides
sqrt(7.875) = 2.81 which matches your answer
let me know if you need me to explain a certain step
i will I'm just reading back and making sure ig to it, math is like y worst subject
ok, great!
so you square 7.875?
take the square root
sqrt(7.875) which is the opposite of squaring
ok I think I understand :)
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