Find the volume of the given prism, round to the nearest tenth if necessary.
The volume of a rectangular/cuboid prism is \(V_{prism}=l\times w\times h\)
This is a cube. Volume is equal to the length times width times height. V=lwh
Supply the measurements provided and do the math.
@radar A cube is a rectangular prism with all edges congruent. This is a rectangular prism, since all the edges are of different lengths. For a cube: V = s^3, where s = the length of an edge. For a rectangular prism: V = L * W * H
I am confused
https://gyazo.com/d1c9d57da75778b462c43b9190db3816 Here's the formula in regards to your figure.
Try looking at that first.
269.3
@AnnaLee607 All you need to do to find the volume is multiply the length by the width by the depth.
You are correct. Just include the units, cm^3.
Yeah, you got it right. \(\text{Good job!}\) (:
What about this one
You need the volume?
yes
The volume of a prism is the area of the base times the height. The previous problem was a rectangular prism, so the base was a rectangle. The volume was the area of a rectangle (the base) times the height. Here you have a triangular prism. The base is a triangle. The volume is still the area of the base times the height. The difference is that here you need to find the area of a triangle since the base is a triangle. Find the area of the base and multiply by the height.
The base of this triangular prism is an equilateral triangle with side of 13 yd.
|dw:1462901333046:dw|
@AnnaLee607 Are you sure you are asked for the volume, not for the surface area?
@mathstudent55 I stand corrected.
yes, it wants the volume
@radar Thanks, I appreciate your honesty.
Ok. Then you need to find the area of the base.
You have an equilateral triangle that I drew above. The area of a triangle is: \(\large V = \dfrac{1}{2} bh\) To find the area of a triangle, we need a base and a height.
An equilateral triangle is also equiangular. All angles are congruent and measure 60 degrees. |dw:1462901564975:dw|
1/2*169=84.5
We can use the bottom side of 13 yd as the base for finding the area. Now we need a height.
No. The height is not 13 yd.
Since we are using the bottom side as our base, we need the altitude drawn to that base. An altitude of a triangle is a segment that goes from a vertex to the opposite side and is perpendicular to the opposite side. |dw:1462901672321:dw|
In an equilateral triangle, an altitude bisects the opposite side and also bisects the angle of the vertex it starts at. |dw:1462901826499:dw|
Notice that the two triangles created by the altitude h are 30-60-90 triangles.
The ratio of the sides of a 30-60-90 triangle is \(\Large 1~:~\sqrt 3~:~ 2\)
The sides are in order: short leg : long leg : hypotenuse
The ratio above shows that the long leg is \(\sqrt 3\) times the length of the short leg.
Since the short leg of the 30-60-90 triangle is 6.5 yd, the long leg is \(6.5 \sqrt 3\) yd. The long leg of the 30-60-90 triangle is the height of the equilateral triangle. \(6.5 \sqrt 3 \approx 11.258\) |dw:1462901986499:dw|
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