Question

I need help with factoring.

Answer 1

what is the highest value that will divide into 4x^2 and 20x?

Answer 2

Ok so question 3 in the first attachment would be (x-6)(x-6) in factored form because
-6+-6=-12 and -6*-6=36

Answer 3

x-6 is not an answer

Answer 4

So the answer would be D

Answer 5

oh (m-6)^2?

Answer 6

I know I was replacing M with X

Answer 7

okay

Answer 8

Yes

Answer 9

what about the others?

Answer 10

To factor, find out what multiple each term have in common. For the first one (4x^2+20x), 4x^2 and 20x have a 4x in common (as on both can be divided by 4x evenly). So factoring out 4x from the equation will give you 4x(x+5)

For the second one (m^2-12m+36), you only look at the coefficients. To factor this, the coefficient of the squared term must be one, which it is. Next look at the constant (36) and the m coefficient (-12) you want to find two whole numbers that multiply to make 36 and add to make 12. -6 and -6 are the two numbers. So the factored form will look like (m-6)(m-6)=(m-6)^2

196=14^2 so
(y^2-196)=(y^2-14^2)=(y+14)(y-14)

Same as the second 8 and 1 multiply to make 8 and add to make 9
So the factored form is (x+1)(x+8)

Answer 11

Ok 1st question in the 1st attachment the x intercepts are 0 and -5 so the answer is. . .
4x(x+5)

Answer 12

Thanks for the help guys!

Answer 13

Umm yeah no problem. . .

Answer 14

100%!!

Answer 15

^~^ thats good