Question

Solve 2 log7 5 + log7 x = log7 100

Answer 1

log rules \[\large\rm \log_b x + \log_b = lob_b ( x \cdot y)\]
addition to multiplication ^
\[\large\rm \log_b x - \log_b = lob_b ( \frac{x}{ y})\]
subtraction <----> division ^
\[\large\rm \log_b x = lob_b y ~~~~~ \rightarrow \cancel{\log_b} x = \cancel{\log_b} y~~~ \rightarrow x=y\]

Answer 2

y missed there above from second terms

Answer 3

so which rule would you apply ?

Answer 4

oh yeah thanks

Answer 5

np

Answer 6

Wait so would i use the addition to multiplication rule? I'm sorry im terrible at this stuff

Answer 7

log rules \[\large\rm \log_b \color{Red}{x} + \log_b \color{blue}{y} = log_b ( \color{ReD}{x} \cdot \color{blue}{y})\]
addition to multiplication ^
\[\large\rm \log_b \color{reD}{x} - \log_b \color{blue}{ y}= log_b ( \frac{\color{red}{x}}{\color{blue}{ y}})\]
subtraction <----> division ^
\[\large\rm \color{pink}{\log_b} \color{Red}{x} = \color{pink}{log_b} \color{blue}{y} ~~~~~ \rightarrow \cancel{\color{pink}{\log_b}} \color{red}{ x} = \cancel{\color{pink}{\log_b}}\color{blue}{ y}~~~ \rightarrow x=y\]

Answer 8

yes that's correct

Answer 9

sorry about these typos...

Answer 10

\[ \log_7 5 + \log_7 x = \log_7 100\] is this your question ?

Answer 11

or is it \[ 2\log_7 5 + \log_7 x = \log_7 100\] ?

Answer 12

So would it be something like
log(7)25x=log(7)100

Answer 13

its the second equation you typed

Answer 14

yes that's correct
i thought 2 represent the number of question
like question #2
\[\large\rm \color{blue}{y} \log_b \color{red}{ x}= \log_b \color{Red}{x}^\color{blue}{y}\]exponent rule

Answer 15

\[\log_7 (25x)= \log_7 100\]

Answer 16

Oh okay thank you for your help though! i got x=4

Answer 17

looks good. good job!