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Mathematics 8 Online
OpenStudy (thatlilmathgirl12xd):

which of the following is the value of x to the nearest tenth?

OpenStudy (thatlilmathgirl12xd):

OpenStudy (thatlilmathgirl12xd):

A. 2.8 B. 4.2 C. 4.8 D. 6.9

OpenStudy (welshfella):

i#m assuming the line length 14 is a tangent to the circle Right?

OpenStudy (bmk614):

If you use the Pythagorean theorem, \[a^2+b^2=c^2\] \[x^2+14^2=(x+10)^2\] Now solve for x.

OpenStudy (welshfella):

if so we have a right angled triangle so (x + 10)^2 = x^2 + 14^2

OpenStudy (thatlilmathgirl12xd):

That is what I thought to do but the last time I answered a similar question using that approach I got it wrong so I was wondering if there was another way to solve it.

OpenStudy (anonymous):

so this is the right way to solve it sure

OpenStudy (thatlilmathgirl12xd):

Iis it? I'm not sure at all.

OpenStudy (anonymous):

why try and i will check it than is right or not - ok. ?

OpenStudy (bmk614):

I can't think of another way myself.

OpenStudy (thatlilmathgirl12xd):

I tried 196-100= square root of 96 and got 9.7

OpenStudy (thatlilmathgirl12xd):

am I using the wrong formula?

OpenStudy (welshfella):

yea there is a theorem linking then square of the tangent to a line pasing through the circle but the pythagoras way is the easiest

OpenStudy (welshfella):

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OpenStudy (welshfella):

i think its a^2 = c(b + c)

OpenStudy (welshfella):

so here we have 14^2 = 10(10+2x)

OpenStudy (welshfella):

giving x = 4.8

OpenStudy (welshfella):

well aths one of the choices so maybe my memory serves me correctly!

OpenStudy (welshfella):

yea that gives the same result as the pythagoras method

OpenStudy (welshfella):

OK?

OpenStudy (welshfella):

r u still there?

OpenStudy (thatlilmathgirl12xd):

I'm sorry I'm back.

OpenStudy (thatlilmathgirl12xd):

but your explanation makes sense thank you!

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