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OpenStudy (tori1423):
A is known to be 6,500 feet above sea level; AB = 600 feet. The angle at A looking up at P is 20°. The angle at B looking up at P is 35°. How far above sea level is the peak P?
Find the height of the mountain peak to the nearest foot.
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10 years ago
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OpenStudy (anonymous):
|dw:1462925580419:dw|
height of P above see level=h+6500
10 years ago
OpenStudy (tori1423):
cot 20- cot 35 = .1205 @surjithayer
10 years ago
OpenStudy (anonymous):
how you calculated?
10 years ago
OpenStudy (tori1423):
.9397-.8192
10 years ago
OpenStudy (anonymous):
\[\cot20=\cot \left( 90-70 \right)=\tan 70\]
similarly cot 35=tan 55
10 years ago
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OpenStudy (tori1423):
im so confused so what do i solve for
10 years ago
OpenStudy (anonymous):
you know tan 45=1
tan 70 is >1
10 years ago
OpenStudy (tori1423):
yes
10 years ago
OpenStudy (anonymous):
tan 70=2.7475
10 years ago
OpenStudy (anonymous):
tan 55=1.4281
10 years ago
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OpenStudy (tori1423):
So how do i find h?
10 years ago
OpenStudy (anonymous):
\[h=\frac{ 600 }{ \cot 20-\cot 35 }=\frac{ 600 }{ \tan70-\tan 55 }=?\]
10 years ago
OpenStudy (tori1423):
454.75?
10 years ago
OpenStudy (anonymous):
you have to find height of P above see level.
so add 6500 ft
10 years ago
OpenStudy (tori1423):
6954.75
10 years ago
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OpenStudy (anonymous):
when you round to nearest ft ,what you get?
10 years ago
OpenStudy (tori1423):
6955
10 years ago
OpenStudy (anonymous):
correct.
10 years ago
OpenStudy (tori1423):
THANK YOU
10 years ago
OpenStudy (anonymous):
yw
10 years ago
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