Question

......

Answer 1

The square of a number exceeds that number by 12. Which of the following equations is used in the process of solving this problem?
I'm not sure.

Answer 2

x^2 = x + 12

Answer 3

try x values likes 2, 3 ,4 and see what makes the expression equivalent.

Answer 4

Your answers would be 4 and -3

Answer 5

for example x = 2

2^2 = 2 +12 , so 4 = 16 which is not true.

Answer 6

You can solve this algebraically by just recognising you can take x^2 = x + 12, put it into standard form and solve as a quadratic.

Answer 7

Than probably \(x^2+12=x\) would work :#

Answer 8

yep that would work

Answer 9

Thanks cx

Answer 10

Np :)

Answer 11

I don't think your equation works @AloneS, hm

Answer 12

maybe x^2 -12 = x

Answer 13

Yes @latinC that would work

Answer 14

x^2-x-12 =0

Answer 15

I dont' have that as my asnwer choice /.<

Answer 16

wait @Erak how did u get there?

Answer 17

What are your answer choices?

Answer 18

\[x=x^2+12\]
\[x^2=x+12\]
\[x^2+12=x\]

Answer 19

It'd be the second one like @sweetburger said above

Answer 20

Hay, x^2+12=x sounds right

Answer 21

I'll go wiht mine.
Alright.

Answer 22

:/ I'm almost certain the second one is correct

Answer 23

あなたは自分を疑う場合にのみ、問題の出生フルーツを行います

Answer 24

?

Answer 25

Ancient, yet accurate

Answer 26

Only when you doubt yourself do problems occur

Answer 27

For example, going with the equation I think is right: x^2 = x + 12

If we use x = 4, we see that

4^2 = 4 + 12
16 = 16

The square of 4, 16, exceeds itself by 12.