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Mathematics 17 Online
OpenStudy (volleyballlover55):

see the picture please

OpenStudy (volleyballlover55):

jimthompson5910 (jim_thompson5910):

This calculator is pretty handy at computing the distance between any two points http://www.mathportal.org/calculators/analytic-geometry/distance-and-midpoint-calculator.php

jimthompson5910 (jim_thompson5910):

let me know if it helps or not

OpenStudy (volleyballlover55):

i don't really get it.. do you know what the answer is?

jimthompson5910 (jim_thompson5910):

are you able to type in the numbers in the boxes? The numbers correspond to the coordinates of the points

jimthompson5910 (jim_thompson5910):

the calculator then shows step by step how to get the distance

OpenStudy (volleyballlover55):

no it doesn't let me type in numbers

jimthompson5910 (jim_thompson5910):

try this then http://www.mathwarehouse.com/calculators/distance-formula-calculator.php

jimthompson5910 (jim_thompson5910):

the two points you'll enter are (-1,5) and (4,1)

jimthompson5910 (jim_thompson5910):

this is what I get when I use the second link http://prntscr.com/b2nf11

OpenStudy (volleyballlover55):

i got 6.4!

jimthompson5910 (jim_thompson5910):

So the calculator is saying the exact distance (in terms of radicals) is \[\Large \sqrt{41}\] which is approximately equal to `6.403124237` round that to the nearest tenth

jimthompson5910 (jim_thompson5910):

yep 6.4 is the answer

OpenStudy (volleyballlover55):

awesome! can you help me with some more please @jim_thompson5910 ? :)

jimthompson5910 (jim_thompson5910):

sure

OpenStudy (volleyballlover55):

ok!

OpenStudy (volleyballlover55):

jimthompson5910 (jim_thompson5910):

are you able to find the sides of that triangle?

OpenStudy (volleyballlover55):

no..

jimthompson5910 (jim_thompson5910):

going from Joan to Gary, how many units do you count out? Count the number of spaces between the points

OpenStudy (volleyballlover55):

5?

jimthompson5910 (jim_thompson5910):

yep, how about from Gary to Kash?

OpenStudy (volleyballlover55):

8

jimthompson5910 (jim_thompson5910):

ok now we must use the distance formula to find the distance from Joan to Kash. Use that calculator and tell me what you get

OpenStudy (volleyballlover55):

whats are the two coordinates for both ?

jimthompson5910 (jim_thompson5910):

I'll show you how to find Joan's coordinates. You tell me Kash's coordinates Start at where the x and y axis cross. Notice you do NOT move left or right. You only move straight up. So because you don't move left or right, the x coordinate is 0. You move up 6 units so the y coordinate of Joan's location is 6 so the point where Joan is at is (0,6) hopefully this makes sense? If so, then tell me Kash's location in terms of (x,y) point.

OpenStudy (volleyballlover55):

wait so whats the 5 and 8 for?

jimthompson5910 (jim_thompson5910):

that will come later

jimthompson5910 (jim_thompson5910):

5 and 8 are the side lengths of the triangle. We're trying to find the third side. We need the distance formula (which means we need the coordinates of the points)

jimthompson5910 (jim_thompson5910):

The ultimate goal is to find the perimeter of this triangle

OpenStudy (volleyballlover55):

oh ok..

jimthompson5910 (jim_thompson5910):

so do you see how I got (0,6) for Joan's location?

OpenStudy (volleyballlover55):

yea...

jimthompson5910 (jim_thompson5910):

where is Kash located? what are his coordinates?

OpenStudy (volleyballlover55):

i got 5,1?

jimthompson5910 (jim_thompson5910):

Start at where the x and y axis cross. move to the right 5 units. The x coordinate is 5 move down 2 units. The y coordinate is -2 so Kash is located at (5,-2) agreed?

OpenStudy (volleyballlover55):

agreed!

jimthompson5910 (jim_thompson5910):

so to recap so far Joan is at (0,6) Kash is at (5,-2) use the distance formula calculator and plug in those coordinates

OpenStudy (volleyballlover55):

i got 9.433981132056603

jimthompson5910 (jim_thompson5910):

add that to the other sides 5+8+ 9.433981132056603 = 22.4339811320567

jimthompson5910 (jim_thompson5910):

the perimeter is approximately 22.4339811320567 so she travels roughly 22 miles I rounded to the nearest whole number

OpenStudy (volleyballlover55):

awesome! What is the exact distance from (−5, 1) to (3, 0)? square root of 63. units square root of 65. units square root of 67. units square root of 69. units

jimthompson5910 (jim_thompson5910):

use the calculator and it will step you through it to the answer

OpenStudy (volleyballlover55):

i got 65!

jimthompson5910 (jim_thompson5910):

\(\Large \sqrt{65}\) I think you mean?

OpenStudy (volleyballlover55):

right i just didn't want to do that... lol :)

jimthompson5910 (jim_thompson5910):

you can write `sqrt(65)` to mean \(\Large \sqrt{65}\)

jimthompson5910 (jim_thompson5910):

but yes I got \(\Large \sqrt{65}\) as well

OpenStudy (volleyballlover55):

ok! next :)

OpenStudy (volleyballlover55):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

go ahead

OpenStudy (volleyballlover55):

The leg of a right triangle is 5 units and the hypotenuse is 8 units. What is the length, in units, of the other leg of the triangle? square root 39 units 39 units square root 89 units 89 units

jimthompson5910 (jim_thompson5910):

I'm assuming your teacher has taught you the Pythagorean Theorem? or no?

OpenStudy (volleyballlover55):

nope

jimthompson5910 (jim_thompson5910):

so you've never heard of it til now?

OpenStudy (volleyballlover55):

well I've heard of it but i don't know what it is.. or how to use it

jimthompson5910 (jim_thompson5910):

This page may be of help. If not, then let me know https://www.mathsisfun.com/pythagoras.html btw, `Pythagoras' Theorem` and `Pythagorean Theorem` are the same thing, just slightly different name

OpenStudy (volleyballlover55):

ok and no the website doesn't help

jimthompson5910 (jim_thompson5910):

do you see how they put squares up to the sides of the triangle?

jimthompson5910 (jim_thompson5910):

like here for example https://www.mathsisfun.com/geometry/images/triangle-3-4-5-pyth.gif

jimthompson5910 (jim_thompson5910):

the idea is that the blue square (16) adds to the yellow square (9) to get the red square (25) 9+16 = 25

jimthompson5910 (jim_thompson5910):

why is this important? because it allows us to find the length of unknown sides in right triangles

OpenStudy (volleyballlover55):

ok so can we answer the question..

jimthompson5910 (jim_thompson5910):

do you see how in the 3,4,5 triangle we have 3^2 + 4^2 equal to 5^2 ?

OpenStudy (volleyballlover55):

ok..

jimthompson5910 (jim_thompson5910):

Is it possible that you're in the wrong lesson? A few lessons ahead maybe?

jimthompson5910 (jim_thompson5910):

it seems strange your teacher wants you to do homework on topics the teacher hasn't covered yet

OpenStudy (volleyballlover55):

yea i know.. I'm homeschooled btw

OpenStudy (volleyballlover55):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

|dw:1462948455242:dw|

jimthompson5910 (jim_thompson5910):

`The leg of a right triangle is 5 units and the hypotenuse is 8 units` |dw:1462948499027:dw|

jimthompson5910 (jim_thompson5910):

|dw:1462948511123:dw|

jimthompson5910 (jim_thompson5910):

Using the pythagorean theorem, we can say... \[\Large a^2 + b^2 = c^2\] \[\Large 5^2 + x^2 = 8^2\] \[\Large 25 + x^2 = 64\] solve for x and tell me what you get

OpenStudy (volleyballlover55):

i have to solve for x for each of them?

jimthompson5910 (jim_thompson5910):

no those are my steps. They all link together (eg: notice how 5^2 turns into 25, 8^2 into 64)

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