Question

@jim_thompson5910 can u help me solve this one? :3

Answer 1

Solve\[ 3x^2+7x-14=0 \]by completing the square. What are the solutions?

Answer 2

notice how the equation is in the form ax^2 + bx + c = 0

Answer 3

where in this case

a = 3
b = 7
c = -14

Answer 4

plug a & b into this formula

h = -b/(2a)

and tell me what h is

Answer 5

let me know if you're stuck @AloneS

Answer 6

Okay so like this?
\[\frac{ -7 }{ 2(3)}\]
and my answer is h= -\(\frac{ 7 }{ }\)
@jim_thompson5910

Answer 7

*-*\[\frac{ 7 }{6}\]

Answer 8

h = -7/6, yes

Answer 9

now plug x = -7/6 into the equation
y = 3x^2+7x-14
to find the value of y

Answer 10

Uhh i'm sorry, btu how would i do that?

Answer 11

replace every x with -7/6, then use a calculator to compute

Answer 12

Like this?
\[-\frac{ 7 }{ 6 } \] =3x^2+7x-14

Answer 13

Uhh I’m sorry but I don’t get it still.

Answer 14

\[\Large y = 3x^2 + 7x - 14\]
\[\Large y = 3{\color{red}{x}}^2 + 7{\color{red}{x}} - 14\]
\[\Large y = 3\left({\color{red}{-\frac{7}{6}}}\right)^2 + 7\left({\color{red}{-\frac{7}{6}}}\right) - 14\]
Hopefully that clears things up?

Answer 15

yea that's right jim_thompson5910

Answer 16

Wait than what do i do next @jim_thompson5910 :3