Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (aivantettet26):

A 3,500 kg truck accelerates uniformly from 15.00 m/s to 35.00 m/s east. During this acceleration, the track travels 187 m. What is the net force acting on the car during this acceleration.

OpenStudy (agent0smith):

Use one of the equations of motion to find acceleration. Then use net force = ma.

OpenStudy (aivantettet26):

What confuses me is how to deal with the 2 accelerations.

OpenStudy (aivantettet26):

Should I just go, F1=ma1 and F2=ma2 then F1 + F2 = Fnet?

OpenStudy (loser66):

a is accelerate and it is = \(V_2-V_1\)

OpenStudy (agent0smith):

There is one acceleration. Two velocities are given. So is displacement. Use them and the v^2 equation to find acceleration.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!