Question

Help me with two questions please? (This is not a test) http://prntscr.com/b2yvdq

Answer 1

For the first one, isolate for x by moving the 9 over and taking the square root of it. You should get two numbers.

Answer 2

That would be using the inverse operations.

For the second one, use the quadratic formula.

Answer 3

\[x^2=9\]
+9 +9
\[x=\sqrt{9,-9}\]
x*x=9 sqare root of 9 is 3
\[x=3,-3\]

For number one ^ that is correct, right?

Answer 4

The answers are correct but the work is off a bit.

x^2 = 9

x = +/- √9

x = +3 or -3

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Answer 5

What you wrote is the correct work?
I don't understand the second part.
x = +/- √9

Answer 6

The technique is the square root of both sides.

http://www.coolmath.com/algebra/09-solving-quadratics/04-solving-quadratic-equations-square-root-01

Answer 7

I did the problem that way because the other helper began that way.

Here is how I would do the problem.

Answer 8

x^2 - 9 = 0

Factor the difference of the two squares

(x + 3) * (x - 3) = 0

Zero Product Property

x + 3 = 0 or x -3 = 0

x = -3 or x = 3

So, 3 and -3.

Answer 9

Here is how the Zero Product Property looks:

Answer 10

Ah. Okay. Thank you! ^-^

Answer 11

You are welcome.

Have you done the second problem?

Answer 12

Not yet. Gimme 1 moment

Answer 13

For the second one, using the quadratic formula, I know a=1,b=4 and c=2
but I don't know how to solve it..

Answer 14

or show my work..

Answer 15

x² + 4x + 2 = 0 will not factor.

The Quadratic Formula is necessary to get the answers.

Answer 16

Attached is a copy of the formula.

Answer 17

In x² + 4x + 2 = 0,

a = 1
b = 4
and
c = 2


Does that make sense, @Ms-Brains

Answer 18

Yup.

Answer 19

http://prntscr.com/b2zqja Like this?

Answer 20

@Directrix

Answer 21

Just a second while I check.

Answer 22

√2 - 2 and - √2 - 2
Yes.

Answer 23

I got what you did. I just put the radicals first for some reason.

Answer 24

Thanks for all the help. o.o

Answer 25

Anytime.