Question

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Answer 1

Start with the area formula, A = lw

Answer 2

@Atrineas

Answer 3

but L=3-2w

Answer 4

close, it's l = 2w - 3

Answer 5

So take that whole l and put it into the equation. You also are given the A

Answer 6

the whole equation?

Answer 7

So in A = lw, replace "l" with what I just put

Answer 8

so (2w-3)*w=65ft^2

Answer 9

yeah

Answer 10

Simplify that and solve for w

Answer 11

is the simplified form 2w^2*3w

Answer 12

when you use the "rainbow" method, you multiply w into 2w and -3 separately

Answer 13

2w^2 and then -3w

Answer 14

so your equation would be 65 = 2w^2 - 3w. Try to get w by itself

Answer 15

would i square root the 2w^2

Answer 16

or use quadractic equation

Answer 17

well in this case, you can recognise you can move the 65 over to the right side to create a quadratic

Answer 18

so is it -5, 13/2

Answer 19

Let w be the width.
Then,
\[w (2 w-3)=65 \]
Solve the above for w.
The length is 2 w-3 .

Answer 20

\[w=\frac{13}{2} \]

Answer 21

so its only 2w-3=65?

Answer 22

Actually I personally would still just treat it as a quadratic and use the quadratic formula

Answer 23

Solve the following for w:\[2 w^2-3 w=65 \]

Answer 24

w=-5,13/2

Answer 25

yeah

Answer 26

so how is there 2 widths

Answer 27

But of those two, which is the realistic one in your situation?

Answer 28

-5

Answer 29

Can you have a width of -5 ft? Does that logically make sense? In word questions like these it matters

Answer 30

oh no lol

Answer 31

so w=6.5

Answer 32

yeah, and to find length, you would sub that w back into that equation we made up there

Answer 33

it works

Answer 34

how do i find the length

Answer 35

nevermind thank you