Lead me...
on what
What is the value of\[ b^2 - 4ac\] for the following equation \[x^2 + 5x + 4 = 0\] Uhhh
that's in standard form, where a^2 + bx + c = 0
Yea?
x^2 = a ; 5x = b ; 4 = c
What it the next step?
so a = 1, b = 5, c = 4, you only use the coefficients. You basically just plug in those numbers into the equation
and solve?
yeah, you'll end up with a number
@erak this way? 1 + 5+ 4 = 0
so in b^2 - 4ac, you plug in the numbers I said like so: 5^2 - 4(1)(4)
Oh okay 9 is my asnwer :3
9 is correct
Thanks.
I agree with Erak: "Erak Best Response Medals 1 so a = 1, b = 5, c = 4, you only use the coefficients. You basically just plug in those numbers into the equation" But what equation? you are to focus solely on the "discriminant," which is b^2 - 4ac. You are not solving this; rather, you are looking to find the value of b^2 - 4ac. It's 9. You don't need or want the square root of 9 here, so omit the 3.
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