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Mathematics 19 Online
alones (alones):

Lead me...

OpenStudy (austinwst13):

on what

alones (alones):

What is the value of\[ b^2 - 4ac\] for the following equation \[x^2 + 5x + 4 = 0\] Uhhh

OpenStudy (erak):

that's in standard form, where a^2 + bx + c = 0

alones (alones):

Yea?

OpenStudy (latinc):

x^2 = a ; 5x = b ; 4 = c

alones (alones):

What it the next step?

OpenStudy (erak):

so a = 1, b = 5, c = 4, you only use the coefficients. You basically just plug in those numbers into the equation

alones (alones):

and solve?

OpenStudy (erak):

yeah, you'll end up with a number

alones (alones):

@erak this way? 1 + 5+ 4 = 0

OpenStudy (erak):

so in b^2 - 4ac, you plug in the numbers I said like so: 5^2 - 4(1)(4)

alones (alones):

Oh okay 9 is my asnwer :3

OpenStudy (erak):

9 is correct

alones (alones):

Thanks.

OpenStudy (mathmale):

I agree with Erak: "Erak Best Response Medals 1 so a = 1, b = 5, c = 4, you only use the coefficients. You basically just plug in those numbers into the equation" But what equation? you are to focus solely on the "discriminant," which is b^2 - 4ac. You are not solving this; rather, you are looking to find the value of b^2 - 4ac. It's 9. You don't need or want the square root of 9 here, so omit the 3.

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