Solve the following quadratic equation using the quadratic formula. Which of the following expressions gives the numerators of the solutions?

Question

alones · Answer

$$10x^2 - 19x + 6 = 0$$

kittiwitti1 · Answer

a. $\text{What "following expressions"?}$
b. The quadratic formula for variable $x$ is the following: $x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$. Note that the discriminant is under the radical... $\sqrt{b^{2}-4ac}$

kittiwitti1 · Answer

so for this equation:
a = 10
b = -19
c = 6$$x=\frac{-(-19)\pm\sqrt{(-19)^{2}-4(10)(6)}}{2(10)}$$

kittiwitti1 · Answer

simplified$\rightarrow$$$\frac{19\pm\sqrt{361-240}}{20}$$

alones · Answer

Oka thanks, let me solve that :3

alones · Answer

Okay i got 19 ± 11

johnweldon1993 · Answer

*Over 20! Don't forget that :)*

$$\large \frac{19 \pm 11}{20}$$

kittiwitti1 · Answer

But they just want the numerator, right? @johnweldon1993

johnweldon1993 · Answer

Reasons why I should read the full question first >.< Thank you @kittiwitti1 :)

kittiwitti1 · Answer

lol P: no problem

anonymous · Answer

Refer to the attachment from Mathematica.