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Mathematics 22 Online
OpenStudy (csubero):

@LatinC https://gyazo.com/2bf6605f6facb6ba0fce2c77a6ee00fa

OpenStudy (csubero):

@Kainui

OpenStudy (latinc):

think fractions

OpenStudy (csubero):

how would it be in fractions??

OpenStudy (csubero):

@latinC

OpenStudy (latinc):

42/70

OpenStudy (csubero):

wait so you divide those??

OpenStudy (latinc):

yes

OpenStudy (csubero):

I did I got 0.6

OpenStudy (csubero):

@latinC https://gyazo.com/808e381e3f0ee9a5d5f0c80a7a406231

OpenStudy (erak):

So find the perimeter of the two half circles, which add up to make a full circle. You would use 2pi*r, where pi=3.14, and r=2d. d is given. Then you would just add the two sidelengths of the rectangle.

OpenStudy (anonymous):

\[\frac{42}{70}=\frac{3}{5}=60 \% \]

OpenStudy (csubero):

thanks bro

OpenStudy (latinc):

\[1/2*h*b =area of a \triangle \]

OpenStudy (latinc):

start by doubling your answer 24*2

OpenStudy (latinc):

divide it my your base since you have that. --> 48/2 =?

OpenStudy (csubero):

im really stuck on this one

OpenStudy (csubero):

@latinC

OpenStudy (csubero):

@ganeshie8

OpenStudy (latinc):

first find the area of the two circles pi*r^2

OpenStudy (latinc):

|dw:1463024844679:dw| if you don't understand this let me know

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