Okay same thing, I have an idea of the answer But i am not sure. Given the exponential equation 3^x = 27, what is the logarithmic form of the equation in base 10? x = log base 10 of 3, all over log base 10 of 27 x = log base 10 of 27, all over log base 10 of 3 x = log base 2 of 3, all over log base 2 of 27 x = log base 2 of 10, all over log base 2 of 3
@galaxystare
@Roxy.girl
I put B
x = log base 10 of 3, all over log base 10 of 27 x=log103log1027 x = log base 10 of 27, all over log base 10 of 3 log1027log103 x = log base 2 of 3, all over log base 2 of 27 x = log base 2 of 10, all over log base 2 of 3
so i would say b ya
r u sure haha this is my seg exam i have to pass
@MrNood what do you think
Yup your right :)
bless :') thank you how about this? What are the explicit equation and domain for a geometric sequence with a first term of 4 and a second term of −8? an = 4(−2)n − 1; all integers where n ≥ 0 an = 4(−2)n − 1; all integers where n ≥ 1 an = 4(−12)n − 1; all integers where n ≥ 1 an = 4(−12)n − 1; all integers where n ≥ 0
i think its B
\[\log a ^{m} = m \log a\] Just start with 3^x use my equation to write log 3^x in another way
Without explanations of WHY you think this or that, "I think it's B" responses make very little sense.
Because base of 10 and 3^x=27 is also log10 27=x
3^x = 27 is in exponential form. Take the common log of both sides of this equation, applying rules of logs. Show your results, please.
log (3^x) = log 27. Solve for x, please.
i dont understand
@mathmale x = 3?
Please separate what you understand and what you don't. Then I'd be happy to provide further explanations. Yes, x=3 is correct, but I'd like to know how you arrived at that.
because it 3 x 3 x 3 = 27
that's correct, but it does not follow the instructions that came with this problem: "what is the logarithmic form of the equation in base 10?" You must apply common logs to arrive at the correct answer. Please note that I have already given you hints regarding what to do; review this conversation, please.
Wait. I already have the answer to this. Can you help with another if i post a different question?
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