Question

i need help on reducing a fraction
k+7
---
4k+28

Answer 1

okay so at the bottom you've got 4k+28

if you notice, we can factor out a 4

Answer 2

ok

Answer 3

So the bottom becomes this \[4(k+7)\] can you see why?

Answer 4

yes

Answer 5

if you multiply 4*k+4*7 you get 4k+28

Answer 6

now here's what we have

\[\frac{ (k+7) }{ 4(k+7) }\]

Answer 7

so @Captain_Deadpool2653 because (k+7) is in both the numerator and denominator, you end up getting

\[\frac{ (\cancel\k+\cancel\7) }{ 4 \cancel\k+\cancel\7 } = \frac{ 1 }{ 4 }\]

Answer 8

thanks that really helped

Answer 9

no problem