Help ?
So they give you P, R, and N R = Rate N = Now many payments that year (in this case) P = Starting Price Do you see those 3 quantities to complete #1?
R=3% N=$39,145 P=$39,145
For N, it's how it's compounded that year. For example, if it's compounded quarterly, that's 4 times a year; which means N = 4. Your problem says monthly, which is 12 times a year; making N = 12
Oh okay so fro number one I would put R=3% N=12 P=$39,145
Yep, so plugging those into the equation will get you number one (No t value was given, but that's no problem)
Okay one sec
like this? A(t)=39,145(1+3(12))
Yeah, just remember the exponent; \[A(t) = $39,145(1+\frac{ .03 }{ 4 })^{4t}\] Remember N was 4, not the example 12. And 3% needed to be converted into a decimal
ohh okay hold on one sec
okay I did it could you help me with 2 and 3
Hmm, let's see... Note: A(t) = Future Value So number 2 asks how many months until you pay the car down to $10,000. So we just use the same equation from number 1 and set it equal to $10,000 (That's our future value)
A(t)=39,145(1+.03/4)^4t=10,000 like this?
Yep! \[$10,000 = $39,145(1+\frac{ .03 }{ 4 })^{4t}\] Now they want you to solve for t This will be nasty lol, we'll need a calculator probably
;-; oh my lol 10,000=39,145(1+.03/4)^4t what's the first step cx
I would first get that 39,145 to the other side. Since it's being multiplied, what should we do to both sides?
subtract 39,145?
We would divide both sides, since that's the opposite of multiplying. If it was being added, we would have subtracted since that is the opposite
my bad I didn't even think about that lmao
We can do that or first we can do the simple math inside those parenthesis
Then multiply that by $39,145
That seems easier
Okay c: sounds good to me
I hope this goes well, I hate this problem xD \[(1 + \frac{ .03 }{ 4 }) = ?\]
1.0075 for the 1+.03/4
That's what I got. Let's now multiply
39292.5 ?
I got something slightly different; 39438.59
I multiplied 1.0075 by 39000
Ah, recalling: The cost of the car was $39,145
ohhh okay yeah my bad again ;-;
It's find xP
Yes you were right c:
\[10000 = (39438.59)^{4t}\] So far this is what we have if you agree
okay c:
This is where I may not know where to go next >.< There's a 4t in the exponent. Since there is a variable in the exponent, logs must be it. Did you learn about logs in class?
yes i'm learning it right now c:
Yeahhh, I never learned those actually. I think I had one day one class period back in highschool, but never again. I wouldn't want to steer you in the wrong direction with a bad answer
well I can see if someone knows what to do from here if you would like? c:
Yeah, that would be a safer bet
@MathMusician
@Ashleyisakitty
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