Question

When looking at a rational function f of x equals the quantity x minus six times the quantity x plus three times the quantity x plus four all divided by the quantity x plus six times the quantity x minus three times the quantity x minus four, Jamal and Angie have two different thoughts. Jamal says that the function is defined at x = –6, x = 3, and x = 4. Angie says that the function is undefined at those x values. Who is correct? Justify your reasoning.

Answer 1

\[f(x)= (x-6)(x+3)(x+4)\div(x+6)(x-3)(x-4)\] is the equation btw

Answer 2

ok can u foil both sides then synthetic divison :) i can help u through both if need be

Answer 3

If the function is defined at x = –6, x = 3, and x = 4, then the function has a value. When you use these three values, division by zero happens. Therefore the function is not defined at x = –6, x = 3, and x = 4.

Answer 4

so jamie is right because dividing by zero breaks math or is undefined

Answer 5

Thank you both!

Answer 6

no problem

Answer 7

Thank you both!