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Mathematics 8 Online
OpenStudy (volleyballlover55):

see attached file

OpenStudy (volleyballlover55):

OpenStudy (volleyballlover55):

@mathmale @wolf1728 @jim_thompson5910

OpenStudy (smartnerd1111):

what 563 ghost told you it was 10 but i say 8.did you ever look back your revioius question

OpenStudy (ivettef365):

use the pythagoream theorem

jimthompson5910 (jim_thompson5910):

check out this article https://www.mathsisfun.com/pythagoras.html specifically how they set up this triangle https://www.mathsisfun.com/geometry/images/triangle-3-4-5-pyth.gif

OpenStudy (ivettef365):

a^2 + b^2 = c^2

OpenStudy (volleyballlover55):

is the answer 10? @jim_thompson5910

OpenStudy (volleyballlover55):

@ivettef365

OpenStudy (ivettef365):

yes

OpenStudy (smartnerd1111):

yes it is

OpenStudy (ivettef365):

6^2 + 8^2 = 36 + 64 = 100 then square root of 100 = 10

OpenStudy (ivettef365):

good job

OpenStudy (volleyballlover55):

ok next!

OpenStudy (volleyballlover55):

@jim_thompson5910 ?

jimthompson5910 (jim_thompson5910):

Your first task is to find the volume of the cone with diameter of 4 and height of 6.3 diameter = 4 radius = 2 r = 2 height = 6.3 h = 6.3 \[\Large \pi \approx 3.14\] Volume of the cone \[\Large V = \frac{1}{3}*\pi*r^2*h\] \[\Large V = \frac{1}{3}*3.14*2^2*6.3\] \[\Large V = ???\] Tell me what you get.

OpenStudy (volleyballlover55):

23.376!

jimthompson5910 (jim_thompson5910):

very good

jimthompson5910 (jim_thompson5910):

80 cubic cm of water goes in the two glasses. 26.376 cubic cm of water goes in the conical glass on the right. So there is 80 - 26.376 = 53.624 cubic cm of water leftover for the cylindrical glass. So this means that if we want all the water to fill up the glass on the left, with no leftover water or a shortage of water, this means that the volume of the cylinder must be approximately 53.624 cubic cm

OpenStudy (volleyballlover55):

ok so 53.6 is the answer? thats not one of the multiple choices

jimthompson5910 (jim_thompson5910):

53.624 cubic cm is the volume of the cylinder, so V = 53.624 The radius is r = 1.5 because this is half of 3, the diamter. The value of h is unknown \[\Large \pi \approx 3.14\] Volume of the cylinder \[\Large V = \pi*r^2*h\] \[\Large V = 3.14*r^2*h\] \[\Large 53.624 = 3.14*(1.5)^2*h\] Solve for h

OpenStudy (volleyballlover55):

7.5

jimthompson5910 (jim_thompson5910):

you should get 7.59009200283086 which rounds to 7.6

OpenStudy (volleyballlover55):

awesome! next! :)

jimthompson5910 (jim_thompson5910):

So if the height of the cylinder is approximately 7.6 cm, then the volume of the cylinder is approximately 53.624 cubic cm

OpenStudy (volleyballlover55):

OpenStudy (ivettef365):

use pythagoream theorem

OpenStudy (ivettef365):

find the distance from B to C and from C to A

OpenStudy (ivettef365):

pythagoream theorerm a^2 + b^2 = c^2

OpenStudy (volleyballlover55):

ok from b to c.. its (2,2) and from c to A its (4,4)

OpenStudy (volleyballlover55):

am i right?

OpenStudy (ivettef365):

yes from B to C = 2 and from C to A = 4 no use the formula 2^2 + 4^2 = C^2

OpenStudy (ivettef365):

now use ....

OpenStudy (volleyballlover55):

whats c?

OpenStudy (volleyballlover55):

157?

OpenStudy (ivettef365):

c is the hypothenuse of the triangle in this case is the length from A to B

OpenStudy (ivettef365):

2^2 = 4 4^2 = 16 so you have 16 + 4 = 20 so you have 20 = c^2,

OpenStudy (ivettef365):

to isolate C you square both sides so you end up with square root of 20

OpenStudy (volleyballlover55):

ok so what do i need to solve to find my answer?

OpenStudy (ivettef365):

that's it the question is find the length of AB

OpenStudy (ivettef365):

the length of AB = square root 20

OpenStudy (ivettef365):

do you have questions?

OpenStudy (volleyballlover55):

oh yes.. @ivettef365

OpenStudy (volleyballlover55):

OpenStudy (ivettef365):

same thing use the pythagorean theorem

OpenStudy (ivettef365):

it works like this a^2 = one leg of the triangle b^2 = the other leg c^2 = hypothenuse a^2 + b^2 = c^2

OpenStudy (ivettef365):

now you have the information of one of the leg and the hypothenuse

OpenStudy (volleyballlover55):

14cm

OpenStudy (ivettef365):

that is the hypothenuse

OpenStudy (volleyballlover55):

ok so then what do i need to solve to get an answer?

OpenStudy (ivettef365):

just plug in numbers on equation 12^2 + b^2 = 14^2 solve for b

OpenStudy (ivettef365):

do you know how to solve this ?

OpenStudy (volleyballlover55):

no :(

OpenStudy (ivettef365):

ok, start by 12^2

OpenStudy (volleyballlover55):

24

OpenStudy (ivettef365):

no 12^2 is the same as 12 x 12

OpenStudy (volleyballlover55):

oh sorry

OpenStudy (volleyballlover55):

144

OpenStudy (ivettef365):

ok so you have 144 + b^2 = 196

OpenStudy (ivettef365):

now you subtract 144 from both sides 144 + b^2 = 196 - 144 -144 ------------------- b^2 = 52

OpenStudy (ivettef365):

you understand up to there?

OpenStudy (volleyballlover55):

yes

OpenStudy (volleyballlover55):

whats b?

OpenStudy (ivettef365):

ok now you square both side, use calculator what is the square root of 52

OpenStudy (volleyballlover55):

7.2!

OpenStudy (ivettef365):

right that is your answer

OpenStudy (volleyballlover55):

OpenStudy (ivettef365):

same thing find the distances using the pythagoream theorem

OpenStudy (volleyballlover55):

this one is confusing me.. i need your help again

OpenStudy (ivettef365):

what is the distance from the school to the mall?

OpenStudy (ivettef365):

what is the distance from the mall to the library?

OpenStudy (volleyballlover55):

-10,8?

OpenStudy (ivettef365):

believe is -10 to 6 ? please check

OpenStudy (volleyballlover55):

oh yea

OpenStudy (ivettef365):

ok so that distance is 16 from -10 to 6 there are 16 squares

OpenStudy (ivettef365):

no the distance from the mall to the library

OpenStudy (ivettef365):

no the distance from the mall to the library

OpenStudy (volleyballlover55):

6,6 or 6,13?

OpenStudy (ivettef365):

just look the points on the x axis

OpenStudy (volleyballlover55):

6,6

OpenStudy (ivettef365):

it is from 15 to -15 please check

OpenStudy (volleyballlover55):

yes i believe so..

OpenStudy (ivettef365):

just look at the line from the mall to the library, the line starts on 15 and ends on -15

OpenStudy (volleyballlover55):

theres no 15 though?

OpenStudy (ivettef365):

look at the line from the school to the mall where does it cross ?

OpenStudy (volleyballlover55):

14

OpenStudy (ivettef365):

it is in between 14 and 16, it does not show number 15 but is in between

OpenStudy (volleyballlover55):

oh ok..

OpenStudy (ivettef365):

ok so the distance from the mall to the library is 30 since starta at 15 and ends on -15

OpenStudy (ivettef365):

so MIke travel 16 miles + 30 miles = 46 miles

OpenStudy (ivettef365):

now we have to find the distance from the school to the library

OpenStudy (ivettef365):

here we us pythagoream theorem 16^2 + 30^2 = c^2 256 + 900 = c^2 1156 = c^2 square root of 1156 = 34

OpenStudy (volleyballlover55):

ok so the answer is 34?

OpenStudy (ivettef365):

the question is how many moire miles did MIke travel than Henry

OpenStudy (ivettef365):

MIke travel 46 miles Henry travel 34 Miles

OpenStudy (volleyballlover55):

12?

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