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OpenStudy (ivettef365):
a^2 + b^2 = c^2
OpenStudy (volleyballlover55):
is the answer 10? @jim_thompson5910
OpenStudy (volleyballlover55):
@ivettef365
OpenStudy (ivettef365):
yes
OpenStudy (smartnerd1111):
yes it is
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OpenStudy (ivettef365):
6^2 + 8^2 = 36 + 64 = 100 then square root of 100 = 10
OpenStudy (ivettef365):
good job
OpenStudy (volleyballlover55):
ok next!
OpenStudy (volleyballlover55):
@jim_thompson5910 ?
jimthompson5910 (jim_thompson5910):
Your first task is to find the volume of the cone with diameter of 4 and height of 6.3
diameter = 4
radius = 2
r = 2
height = 6.3
h = 6.3
\[\Large \pi \approx 3.14\]
Volume of the cone
\[\Large V = \frac{1}{3}*\pi*r^2*h\]
\[\Large V = \frac{1}{3}*3.14*2^2*6.3\]
\[\Large V = ???\]
Tell me what you get.
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OpenStudy (volleyballlover55):
23.376!
jimthompson5910 (jim_thompson5910):
very good
jimthompson5910 (jim_thompson5910):
80 cubic cm of water goes in the two glasses.
26.376 cubic cm of water goes in the conical glass on the right. So there is 80 - 26.376 = 53.624 cubic cm of water leftover for the cylindrical glass.
So this means that if we want all the water to fill up the glass on the left, with no leftover water or a shortage of water, this means that the volume of the cylinder must be approximately 53.624 cubic cm
OpenStudy (volleyballlover55):
ok so 53.6 is the answer? thats not one of the multiple choices
jimthompson5910 (jim_thompson5910):
53.624 cubic cm is the volume of the cylinder, so V = 53.624
The radius is r = 1.5 because this is half of 3, the diamter.
The value of h is unknown
\[\Large \pi \approx 3.14\]
Volume of the cylinder
\[\Large V = \pi*r^2*h\]
\[\Large V = 3.14*r^2*h\]
\[\Large 53.624 = 3.14*(1.5)^2*h\]
Solve for h
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OpenStudy (volleyballlover55):
7.5
jimthompson5910 (jim_thompson5910):
you should get 7.59009200283086 which rounds to 7.6
OpenStudy (volleyballlover55):
awesome! next! :)
jimthompson5910 (jim_thompson5910):
So if the height of the cylinder is approximately 7.6 cm, then the volume of the cylinder is approximately 53.624 cubic cm
OpenStudy (volleyballlover55):
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OpenStudy (ivettef365):
use pythagoream theorem
OpenStudy (ivettef365):
find the distance from B to C
and from C to A
OpenStudy (ivettef365):
pythagoream theorerm a^2 + b^2 = c^2
OpenStudy (volleyballlover55):
ok from b to c.. its (2,2)
and from c to A its (4,4)
OpenStudy (volleyballlover55):
am i right?
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OpenStudy (ivettef365):
yes from B to C = 2
and from C to A = 4
no use the formula 2^2 + 4^2 = C^2
OpenStudy (ivettef365):
now use ....
OpenStudy (volleyballlover55):
whats c?
OpenStudy (volleyballlover55):
157?
OpenStudy (ivettef365):
c is the hypothenuse of the triangle in this case is the length from A to B
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OpenStudy (ivettef365):
2^2 = 4
4^2 = 16
so you have 16 + 4 = 20
so you have 20 = c^2,
OpenStudy (ivettef365):
to isolate C you square both sides so you end up with square root of 20
OpenStudy (volleyballlover55):
ok so what do i need to solve to find my answer?
OpenStudy (ivettef365):
that's it the question is find the length of AB
OpenStudy (ivettef365):
the length of AB = square root 20
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OpenStudy (ivettef365):
do you have questions?
OpenStudy (volleyballlover55):
oh yes.. @ivettef365
OpenStudy (volleyballlover55):
OpenStudy (ivettef365):
same thing use the pythagorean theorem
OpenStudy (ivettef365):
it works like this
a^2 = one leg of the triangle b^2 = the other leg c^2 = hypothenuse
a^2 + b^2 = c^2
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OpenStudy (ivettef365):
now you have the information of one of the leg and the hypothenuse
OpenStudy (volleyballlover55):
14cm
OpenStudy (ivettef365):
that is the hypothenuse
OpenStudy (volleyballlover55):
ok so then what do i need to solve to get an answer?
OpenStudy (ivettef365):
just plug in numbers on equation
12^2 + b^2 = 14^2
solve for b
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OpenStudy (ivettef365):
do you know how to solve this ?
OpenStudy (volleyballlover55):
no :(
OpenStudy (ivettef365):
ok, start by 12^2
OpenStudy (volleyballlover55):
24
OpenStudy (ivettef365):
no 12^2 is the same as 12 x 12
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OpenStudy (volleyballlover55):
oh sorry
OpenStudy (volleyballlover55):
144
OpenStudy (ivettef365):
ok so you have
144 + b^2 = 196
OpenStudy (ivettef365):
now you subtract 144 from both sides
144 + b^2 = 196
- 144 -144
-------------------
b^2 = 52
OpenStudy (ivettef365):
you understand up to there?
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OpenStudy (volleyballlover55):
yes
OpenStudy (volleyballlover55):
whats b?
OpenStudy (ivettef365):
ok now you square both side, use calculator what is the square root of 52
OpenStudy (volleyballlover55):
7.2!
OpenStudy (ivettef365):
right that is your answer
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OpenStudy (volleyballlover55):
OpenStudy (ivettef365):
same thing find the distances using the pythagoream theorem
OpenStudy (volleyballlover55):
this one is confusing me.. i need your help again
OpenStudy (ivettef365):
what is the distance from the school to the mall?
OpenStudy (ivettef365):
what is the distance from the mall to the library?
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OpenStudy (volleyballlover55):
-10,8?
OpenStudy (ivettef365):
believe is -10 to 6 ? please check
OpenStudy (volleyballlover55):
oh yea
OpenStudy (ivettef365):
ok so that distance is 16 from -10 to 6 there are 16 squares
OpenStudy (ivettef365):
no the distance from the mall to the library
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OpenStudy (ivettef365):
no the distance from the mall to the library
OpenStudy (volleyballlover55):
6,6 or 6,13?
OpenStudy (ivettef365):
just look the points on the x axis
OpenStudy (volleyballlover55):
6,6
OpenStudy (ivettef365):
it is from 15 to -15 please check
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OpenStudy (volleyballlover55):
yes i believe so..
OpenStudy (ivettef365):
just look at the line from the mall to the library, the line starts on 15 and ends on -15
OpenStudy (volleyballlover55):
theres no 15 though?
OpenStudy (ivettef365):
look at the line from the school to the mall where does it cross ?
OpenStudy (volleyballlover55):
14
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OpenStudy (ivettef365):
it is in between 14 and 16, it does not show number 15 but is in between
OpenStudy (volleyballlover55):
oh ok..
OpenStudy (ivettef365):
ok so the distance from the mall to the library is 30
since starta at 15 and ends on -15
OpenStudy (ivettef365):
so MIke travel 16 miles + 30 miles = 46 miles
OpenStudy (ivettef365):
now we have to find the distance from the school to the library
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OpenStudy (ivettef365):
here we us pythagoream theorem
16^2 + 30^2 = c^2
256 + 900 = c^2
1156 = c^2
square root of 1156 = 34
OpenStudy (volleyballlover55):
ok so the answer is 34?
OpenStudy (ivettef365):
the question is how many moire miles did MIke travel than Henry