Please help! Will medal and fan!
@Erak
So basically a direct linear variation equation is set up like h(x) = mx You are given both the h(x) and x, just solve for m.
I dont get it, sorry
Okay it tells you h(x) = 4 when x = 16, right? So those are two variables in that equation I put up. We would substitute those variables like so: h(x) = mx 4 = 16m m = ?
4
right?
So in order to get m by itself, in this case you would do 4/16, giving you 1/4 because you would have to divide both sides by 16
Oh opps, I did it the other way around
So now you know the m value is 1/4. Now you can build a general equation for that like so: h(x) = 1/4x Does that make sense so far?
Yeah
Now it's asking you to find x when h(x) = 16, so the equation is set up like so: h(x) = 1/4x 16 = 1/4x x = ?
4
So in this case, you be doing \[16 \div \frac{ 1 }{ 4 }\] Do you know how to divide a fraction?
you make it into a decimal first
Oh god I misread that, it's actually h(x) = 6. My bad. h(x) = 1/4x 6 = 1/4x x = ? And you can use a decimal, giving you 6/.25 = 24.
Or, if you want to learn about dividing fractions, you would flip the second fraction like so \[6 \times \frac{ 4 }{ 1 }\]
Oh right
3/2 or 1 1/2
So that just be 6x4 = 24 in that case
oh
So that' the answer? 24?
@Erak
yeah
Oh okay, thanks!
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