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Mathematics 21 Online
OpenStudy (volleyballlover55):

HELP!!!!!!!!!

OpenStudy (volleyballlover55):

OpenStudy (volleyballlover55):

@undeadknight26 @jim_thompson5910

OpenStudy (anonymous):

Know what the pythagoreom theory is?

OpenStudy (anonymous):

a^2 + b^2 = c^2? That's what you'd do. A and B = the known sides.

OpenStudy (anonymous):

If I remember correctly, that is. Maybe Jim can shed some light on the matter?

OpenStudy (anonymous):

It could be B and C are the known sides and you solve for A.

OpenStudy (volleyballlover55):

@jim_thompson5910

OpenStudy (anonymous):

\[height= \sqrt{113^{2}-15^{2}}\]

jimthompson5910 (jim_thompson5910):

hint: see attached

OpenStudy (volleyballlover55):

what do i have to solve?

jimthompson5910 (jim_thompson5910):

http://assets.openstudy.com/updates/attachments/57354835e4b0dabdb023469a-jim_thompson5910-1463110317279-hint1.jpg \[\Large {\color{red}{x}}^2+{\color{green}{y}}^2={\color{blue}{z}}^2\] \[\Large {\color{red}{x}}^2+{\color{green}{15}}^2={\color{blue}{113}}^2\] \[\Large x^2+225=12769\] \[\Large x^2+225-225=12769-225\] \[\Large x^2=12,544\] \[\Large \sqrt{x^2}=\sqrt{12,544}\] \[\Large x=112\]

OpenStudy (anonymous):

Ah so I was wrong. It was B and C and you solve for A. Makes sense.

OpenStudy (anonymous):

Excellent work as usual Jim.

jimthompson5910 (jim_thompson5910):

Thanks

OpenStudy (volleyballlover55):

yes great work! next! The length of the hypotenuse of a right triangle is 14 inches. If the length of one leg is 6 inches, what is the approximate length of the other leg? 11.5 inches 12.6 inches 15.2 inches 20.0 inches

jimthompson5910 (jim_thompson5910):

Give this one a try |dw:1463110831671:dw|

jimthompson5910 (jim_thompson5910):

the steps will be the same as before, just with different numbers this time

OpenStudy (volleyballlover55):

i still don't get it

jimthompson5910 (jim_thompson5910):

which step are you stuck on?

OpenStudy (volleyballlover55):

all :( especially the beginning..

OpenStudy (volleyballlover55):

i sort of get it more at the end..

jimthompson5910 (jim_thompson5910):

do you see how I set x, y and z to be the side lengths?

jimthompson5910 (jim_thompson5910):

x is unknown y is 15 z is 113

OpenStudy (volleyballlover55):

but why the letters y and z?

jimthompson5910 (jim_thompson5910):

just any 3 letters really. x,y,z makes the most sense for me

jimthompson5910 (jim_thompson5910):

it could be a,b,c or p,q,r or any 3 letters you want

OpenStudy (volleyballlover55):

oh ok...

jimthompson5910 (jim_thompson5910):

the letters are just placeholders for a number example: y is a placeholder for 15

OpenStudy (volleyballlover55):

ok yea i get that.. moving on..

jimthompson5910 (jim_thompson5910):

do you understand what I mean when I write \(\Large x^2\) ?

OpenStudy (volleyballlover55):

no

jimthompson5910 (jim_thompson5910):

it means `x squared` squaring any number means you multiply that number by itself examples \(\Large 7^2\) = 7 squared = 7*7 = 49 \(\Large 9^2\) = 9 squared = 9*9 = 81 \(\Large 14^2\) = 14 squared = 14*14 = 196

OpenStudy (volleyballlover55):

oh yea i get that.. ok next..

jimthompson5910 (jim_thompson5910):

As practice, tell me what \(\Large 16^2\) is equal to

OpenStudy (volleyballlover55):

256

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

so hopefully you can see how I turned \(\Large 15^2\) into \(\Large 225\) ?

OpenStudy (volleyballlover55):

yes...

jimthompson5910 (jim_thompson5910):

and you're able to see how I turned \(\Large 113^2\) into \(\Large 12769\) ?

OpenStudy (volleyballlover55):

yes...

jimthompson5910 (jim_thompson5910):

so you can see how I solved that last equation for x? you understand all the steps?

OpenStudy (volleyballlover55):

I'm pretty sure

jimthompson5910 (jim_thompson5910):

ok you'll use those same steps (just with different numbers) on this next problem

jimthompson5910 (jim_thompson5910):

|dw:1463111890201:dw| \[\Large x^2+y^2 = z^2\] \[\Large x^2+6^2 = 14^2\] solve for x

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