Question

Solve .....this ......quadratic equation -----------------------------------------------------------------------------------(using the quadratic formula.)

Answer 1

@johnweldon1993 here it is

Answer 2

Solve this quadratic equation using the quadratic formula.

2x^2 - 2x = 1
check

Answer 3

XD you did not! @AloneS XD

Well I'm going to sit quietly in the background while you list the steps for me >:D

Answer 4

O.M.G. NOOOOO

Answer 5

Damn i'm dead

Answer 6

it's either that or prove that f+g has a limit at x_0

Answer 7

usiki o.m.g why did u do itttttt >.>

Answer 8

Okay
a,b,c,d
a=2x^2
b=2x
c=1?

Answer 9

let me look , i forgo tthe steps again.brb

Answer 10

I'm going to post them 1 last time :)
You have an equation in the form \(\large ax^2 + bx + c = 0\)

1) Find your coefficients. a = ? b = ? c = ?
2) Write down the quadratic formula \(\large \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
3) Plug in your values
4) simplify if possible

Answer 11

OOooooh thank you *bows*

Answer 12

Yo don't delete it tho

Answer 13

ok * secretly erases*

Answer 14

I won't as long as you get it 100% correct >:D

Answer 15

1 wrong move...POOF...gone >:D
* we are in the fun part of openstudy now lmao

Answer 16

i think the first step should be rewrite the equation in ax^2+bx+C=0 quadratic form

2) Find your coefficients. a = ? b = ? c = ?
3) Write down the quadratic formula \(\large \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
4) Plug in your values
5) simplify if possible

Answer 17

whooa usiki dont' let me look like a slave there.
LOL WELDOONE where is it!! I WANNAA SEE IT

Thansk nnesha well done can earase it cx

Answer 18

?

Answer 19

\[\frac{ -2\sqrt{(-2)^2-4(2)(-1)} }{ 2(2) }\]

Answer 20

okay what's next *scrathes head*

Answer 21

Okay okay so \[\frac{ 2+\sqrt{12} }{ 4 }\]

Answer 22

lets play game
compare this \[\frac{ -2\sqrt{(-2)^2-4(2)(-1)} }{ 2(2) }\]
with \(\large \rm \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)

can you find the difference ?

Answer 23

yay!
difference in what?o.o

Answer 24

nvm i think you don't know how to type plus/minus sign
`/pm`

Answer 25

yea yeaa i do liek this

Answer 26

Oh damn it didn't post\[nesha \pm human\]

Answer 27

\(\color{blue}{\text{Originally Posted by}}\) @AloneS
\[\frac{ -2 \sqrt{(-2)^2-4(2)(-1)} }{ 2(2) }\]
\(\color{blue}{\text{End of Quote}}\)
\[\frac{ \color{red}{-}2 \pm \sqrt{(-2)^2-4(2)(-1)} }{ 2(2) }\]
\(\color{blue}{\text{Originally Posted by}}\) @AloneS
Okay okay so \[\frac{ 2+\sqrt{12} }{ 4 }\]
\(\color{blue}{\text{End of Quote}}\)
what happened to that negative sign ?

Answer 28

what's `b` value in that equation ?? :)

Answer 29

It turned in to postitive :D
lol b=-2
and i got my answer \[x=\frac{ 1\pm \sqrt{32} }{ 24 }\]

Answer 30

`It turned in to postitive :D`
right so it should be
\[\frac{ \color{red}{-}(\color{red}{-2}) \pm \sqrt{(\color{Red}{-2})^2-4(2)(-1)} }{ 2(2) }\]

b is negative and there is another negative sign in quadratic formula

Answer 31

you're tired..right?

Answer 32

Oh ye.. I am tbh.

Answer 33

waaait show it again

Answer 34

i think you mean tto type 4 at the denominator ? \[x=\frac{ 1\pm \sqrt{32} }{ 4 }\]

Answer 35

Oh lol yeaa i didn't reduce it
thansk<3

Answer 36

\[\frac{ \color{red}{-}(\color{red}{-2}) \pm \sqrt{(\color{Red}{-2})^2-4(2)(-1)} }{ 2(2) }\]

simplify this ..again

Answer 37

Oh damn again? ;~;

Answer 38

\(\color{blue}{\text{Originally Posted by}}\) AloneS
It turned in to postitive :D
lol b=-2
and i got my answer \[x=\frac{ 1\pm \sqrt{32} }{ 24 }\]
\(\color{blue}{\text{End of Quote}}\)
yea or can you please explain what happened to 2 at the numerator ? how did you get 32 ?

Answer 39

Nooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo*rips the hair out*

Answer 40

Oh fine i'll explain i mulitplied (-2)by square root 2, than i mulitplied 4*1 which gave me 4, and than multiplied 4*4 which is 16 and i ended up 32