I need help with Geometry! This portfolio is due today and I have a question! How do I know if I need to find the sine, cosine, or tangent of an angle? I know how to do all three I just don't understand which one I have to do. I'll attach my worksheet for examples of questions.
dear friend as regard to your number one question pythagoras theorem will be used to solve it because angle is not giving.whenever you are giving an angle or theta you can now use SOHCAHTOA
but which on do i use sin, cos, or tan?
for the rest of the problems..
Like question 4.
or 5..
Using sine, cosine, or tangent depends on which values are known and which values are unknown. Try filling in this chart: Cosine relates the side ( opposite | adjacent ) to the angle, to the ___________, so I use cosine to solve problems where I know _____________ or ___________ and need the other one. Sine relates the side ( opposite | adjacent ) to the angle, to the ___________, so I use sine to solve problems where I know _____________ or ___________ and need the other one. Tangent relates the side ( opposite | adjacent ) to the angle, to the side ( opposite | adjacent ) so I use tangent to solve problems that do not involve the hypoteneuse. Does that get you straight?
no.. i think im more confused.. can you use one of the problems like 4 and explain why it is the one it is?
for question 4 since we are looking for the opposite side we look for the formular that connects the opposite side and and any other side
now the only two that fit is TOA SOH
TOA wont work because it wont make opp the subject formular SOH
what do you mean we are looking for the opposite side? How do you know that?
wait i think i get what you're saying.
BC is the opposite side
but i dont understand why you'd pick sin over tan?
to check your answer if it is correct use pythagoras to confirm if it will give you the same answer.\[\sin \theta=\frac{ opp }{ hyp}=\sin 32 \frac{ opp }{ 10.6 }=\sin32\times10.6=BC\]
that's not an answer choice
and i still dont understand why you picked sin over tan?
give me a sec
OK, #4: You know angle A, side AC ('adjacent' to A), and side AB (hypotenuse). We are going to take baby-steps on the way to the answer. Can you write two formulas with A=32°, that could solve for unknown BC? Don't worry about whether the answers are in the list for #4 yet, just show me you know how to use the given dat afor a first try to find the answer.
sin(32)= BC/10.6 tan(32)=BC/8.2
Yes, good, you are using sine and tangent correctly. You may have noticed the two choices that use 32° are NOT correct math. Throw those out. And your two good choices are not on the list, so your teacher is messing with you to get you expand your thinking. So maybe 58° is important, but it is not in the figure! any ideas?
I have no idea.
I know how to use the formulas i just get confused on which one i have to use.
This is one of those problems that you mostly have to try all the answers to see if one is right. I can understand your confusion because three answer choices are WRONG math, so you don't learn much. I have to go, but let me try this. the three angles inside a triangle add to 180°. We know one here is a right angle, 90°, so A and B add to 90°. A is 32° so B is 58° (90-32=58) Change your perspective and write the formulas for angle B. Names change now. AB is still the hypotenuse. AC is the side OPPOSITE angle B, and BC is the side ADJACENT. So sine(B) = AC/AB. That is the one formula that will not help you solve the problem, so write out the other two.
So, not knowing which equation to use. It can be tough. Trial and error will help you learn how to choose. Identify what you DO know. See if you can fit it into one of the formulas. Remember, sine of an angle in a right triangle relates the side 'opposite' that is, the side not attached to that angle you are using and the hypotenuse.
this might help you figure out which to use https://www.khanacademy.org/math/trigonometry/trigonometry-right-triangles/intro-to-the-trig-ratios/v/basic-trigonometry
First idea: a right triangle has 3 sides, and we give them names. The hypotenuse is the longest side. There is only one hypotenuse. the name of the other two sides *depends on which angle we use* so: pick an angle ( but *not* the 90 deg angle) then label the sides opposite and adjacent (see video on how to do this)
2nd idea: usually you know one side and want to find another side. you also need to know an angle. using the angle they give you, label all 3 sides. then identify the two sides you will be using: 1 is known, the other you want to find based on the "names" of those two sides, you will know to use sin, cos or tan
I understand what sine cosine and tangent are, i also know how to find them. My only problem is distinguishing which on to use to find the measurement I need. Can you please give me an example question? I attached my worksheet if you want to use one from there. That worksheet is due today and I'm so confused and don't know how to do it but I have to get it done.
There's a memory aid which you might find useful SOH-CAH-TOA : - Sine = Opposite / Hypotenuse cos = Adjacent / Hypotenuse tan = Opposite / Adjacent
@welshfella I already know that. I know how to find the sin, cos, tan of an angle i just don't know which one i have to use in different problems.
Look at your Problem 6. You are given two sides of the triangle. Using angle X, tell us the names of these two sides. That should tell you what formula to use for this problem. I think you just need confidence.
sine right? I think i get what you're saying!!!!
Yes, sine! I hope you did the steps in-between! The _opposite_side_ from X is 11, and the hypotenuse is 32. sine = Opposite Over Hypotenuse, that's all it takes. Go Forth And Conquer!
yep! so would the answer just be 11/32 or do i have to do something else?
write down what you know and what you need to find take an example |dw:1463165693107:dw|
x is the hypotenuse. 2 is opposite. the other is adjacent
angle = 30 . opp = 2 , hyp = x you have OH therefore you need the sine sin 30 = O/H = 2/x
Okay i get it thank you !
yw
I'm having trouble with number 4,5, 7, and 8. Could anyone help?
@mjdennis @welshfella
For #4, go back up and look at my other answers. It really is one where you should look at each answer and try to see if it is true in the formula, because 3 of them are just WRONG. Only one of the choices can be made using the information given.
im trying but its confusing me.. alot
SOHCAHTOA
which one are you doing ?
4.
#5, follow these steps: First, understand the problem. See if the picture and problem match. Good. Focus on the triangle. You know an angle and a side. You want to find the other side. You know nothing about the hypotenuse, but that should be OK; figure out which side is adjacent and which is opposite the angle, and write one of your formulas.
look at choice A: sin 32 = BC/8.2 what are the "names" for BC and side 8.2 using angle 32 as the reference. any idea ?
i still dont know 4.
opp/adj
is sin opp/adj ?
no! cross off choice A
okay
Got it. I have to go. @phi is sharp and asking you the right questions. one step at a time!
okay thanks i really appreciate all your help
look at choice B cos 32 = BC/10.6 what are the names for BC and side 10.6 ?
opp/hyp which is sin
so cross off choice B
and b says its cos.
tan would be BC/8.2, and it wouldnt b e58
and the last choice ?
for the last one the formula makes since but why does it say sin58, shouldnt it be sin 32?
for choice C, we have to be careful tan 58 = 8.2/BC notice they are using angle 58 (which is the unlabeled angle) (the two angles 32+58 will always add up to 90) anyway, when you use angle 58, the names change, the opposite side will be 8.2 and the adjacent side is BC
and yes, choice D would be correct if we used angle 32. But they are being sneaky and using the other angle (which is 58) you know the unlabeled angle is 58 because it is 90-32
lost ?
so is it c? I get what your saying
yes, it is C if we use angle 58, then side 8.2 is opposite and side BC is adjacent do you see that ?
yes. Thanks. Now number 5.
this takes a small amount of thinking, and some trigonometry. First, the trig. in the triangle, what side do we know, and what side do we want to find ?
assuming we use angle 38 as the reference
adjacent
yes, we know adjacent. what side do we want to find ?
t?
yes, we want to find how tall the tree is (the up/down direction) if we know t and add 5 we will get the height of the tree.
that is the "thinking part"
what is the name for side "t" using 38 as the angle ?
opposite
we know adjacent (20) and want to find opposite. what should we use ?
tan?
yes TOA tan = opp/adj or , putting in numbers: tan 38 = t/20 can you find t ? I would first multiply both sides by 20
i dont think i can.?
this part is algebra. \[ \frac{t}{20}= \tan 38 \\20 \cdot \frac{t}{20}= 20 \cdot \tan 38 \] on the left side, that is the same as \[ \frac{20}{20}t= 20 \cdot \tan 38 \]
what is 20/20 ?
the idea is anything divided by itself is 1, and 20 divided by 20 is 1 so you have t = 20 * tan 38 you need a calculator to find t
ok
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