An object is dropped off a building that is 144 feet tall. After how many seconds does the object hit the ground?

Question

alones · Answer

(s = 16t^2)

kendricklamar2014 · Answer

Use the drt formula: $$distance = rate \times  time $$

the_puppet1 · Answer

I think about 6 seconds until it hits the ground

the_puppet1 · Answer

When it is just dropped just count the sec so the answer is 6 seconds

shadowlegendx · Answer

This is ignoring other factors right? Like air resistance

kendricklamar2014 · Answer

Now just substitute: $$144 = 16t^2 * X $$

alones · Answer

Okay i got $$\frac{ 9 }{ t^2 }$$

kendricklamar2014 · Answer

$$s = 16t^2$$
$$144 = 16t^2$$
$$9 = t^2$$
What do you get?

mjdennis · Answer

@AloneS , do back to your first equation.  s is distance, in this case height.
So solve 
144 = 16*t^2
for t
(and throw away the negative answer, since t^2=something has two answers...)

kendricklamar2014 · Answer

@AloneS To solve this problem, all you need to do is find what number squared is equal to 9. Do you understand what I mean by that?

alones · Answer

No sorry i'm confused now

kendricklamar2014 · Answer

Okay, so we need to substitute t^2. What number can we substitute so that x(the number(^2 is equal to 9.

alones · Answer

Uhh   3?

kendricklamar2014 · Answer

Yes, that is correct =)

alones · Answer

YAAAASSS!!!!!FINALLYYYY!!!THANSK KENDRIC<3

kendricklamar2014 · Answer

Your welcome :)

alones · Answer

THNAKS<3