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Mathematics 4 Online
OpenStudy (medina13):

2. Find the standard deviation of the data set below. 17, 16, 56, 50, 14 Please show me step by step.

OpenStudy (math&ing001):

First step, find the mean. You can do that by finding the sum of all the numbers in the data set, then dividing it by the number of elements in your data set.

OpenStudy (medina13):

30.6 ?

OpenStudy (medina13):

@math&ing001

OpenStudy (math&ing001):

Yep, correct ! Second step is to find the variance. To do that you take each number in your data set and you subtract the mean from it. Then square each subtraction, and add the squared numbers all together.

OpenStudy (medina13):

Sooo each number subtract that from 30.6 ?

OpenStudy (math&ing001):

No subtract 30.6 from each number, like x-30.6

OpenStudy (medina13):

Sooo like 17- 30.6? or really x-30.6 Sorry im horrible at math.

OpenStudy (math&ing001):

Yep exactly like 17-30.6 x is just a random variable.

OpenStudy (medina13):

okay ill do that right now

OpenStudy (medina13):

okay i did that, now how do i do the last part?

OpenStudy (medina13):

Then square each subtraction, and add the squared numbers all together.

OpenStudy (math&ing001):

The 5 subtractions you got, you square them. Then you add all those squares. After that, divide the sum by (n-1). That's your variance.

OpenStudy (medina13):

ok i understand all of that besides how to square them..

OpenStudy (math&ing001):

Oh, to square a number is to put it to the power of 2.

OpenStudy (medina13):

okay so -13.6 x 2 ?

OpenStudy (math&ing001):

Not quite, it's looks like this \(\huge{x^2}\)

OpenStudy (medina13):

right, im just having trouble with all of that now, im pretty confused

OpenStudy (math&ing001):

It's totally ok. So in the first example it would be (-13.6)²=184.96

OpenStudy (medina13):

ok so, (-14.6)2 = -29.2 ?

OpenStudy (medina13):

if thats correct, do that to all of them?

OpenStudy (medina13):

did that wrong, i fixed it

OpenStudy (medina13):

213.16 ?

OpenStudy (math&ing001):

Cool !

OpenStudy (medina13):

is the 213.16 correct

OpenStudy (math&ing001):

Yep, correct !

OpenStudy (medina13):

ok, finished alll of that, now i do what

OpenStudy (math&ing001):

You added them and divided by (n-1) too ?

OpenStudy (medina13):

not yet

OpenStudy (math&ing001):

OK when you do tell me what you get =)

OpenStudy (medina13):

i got 1695.2 when adding

OpenStudy (math&ing001):

Didn't check but it seems right.

OpenStudy (medina13):

okay then divide that by one ?

OpenStudy (math&ing001):

You divide by (n-1), n being the number of elements in your data set

OpenStudy (medina13):

1695.2/1 ? now thats where im going to be confused

OpenStudy (medina13):

ohh okay never mind

OpenStudy (medina13):

(5-1) ?

OpenStudy (math&ing001):

Yep !

OpenStudy (medina13):

so i got 4 ? when it comes to (5-1) then what lol

OpenStudy (math&ing001):

So you divide what you got (1695.2) by 4 =)

OpenStudy (medina13):

I got 423.8

OpenStudy (math&ing001):

Yep that would be your variance. Finally you find the square root of the variance, and you have your standard deviation.

OpenStudy (medina13):

Okay how does that work.. lol

OpenStudy (math&ing001):

Standard deviation is \[\sqrt{variance} = \sqrt{423.8}\]

OpenStudy (medina13):

ok, whats that or what do i do from here

OpenStudy (math&ing001):

Just evaluate the square root to get your answer.

OpenStudy (medina13):

okay and thats all ? .-.

OpenStudy (math&ing001):

Yep !

OpenStudy (medina13):

these math terms got me so confused lol thank you so much! ill try figure the last part out

OpenStudy (math&ing001):

You're not supposed to do it by hand just use a calculator :P \(\sqrt{423.8}=20.6\) You're much welcome !

OpenStudy (medina13):

You just saved my life !!!!! Thank you!!!! :D

OpenStudy (math&ing001):

^^

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