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Mathematics 11 Online
OpenStudy (gottennis121):

Will Medal! Linear Equations Question http://screenpresso.com/=EaDZe That's the portfolio since I messed up in the beginning where I tried to start.

OpenStudy (s4sensitiveandshy):

speed = x-axis Distance = y-axis there are two coordinates for Rabbit when speed =30 distance = 1.5 (30,1.5) can you write the coordinate for cheetah :D?

OpenStudy (gottennis121):

Oh wait, I thought I have to put it into an equation? Or am I getting to far ahead of myself?

OpenStudy (agent0smith):

I think you should just post the question since I don't know what you're meant to find.

OpenStudy (gottennis121):

It's a portfolio.

OpenStudy (s4sensitiveandshy):

that's right you need two order pair to find the slope and then y-intercept.

OpenStudy (gottennis121):

Oh, so (70,3.0) for cheetah.

OpenStudy (s4sensitiveandshy):

yes (30,1.5)(70 ,3) use the slope formula \[m=\frac{y_2-y_1}{x_2-x_1}\]

OpenStudy (gottennis121):

May I ask what "m" is representing?

OpenStudy (s4sensitiveandshy):

y=mx+b is slope intercept form( linear equation) where m is the slope and b is y-intercept

OpenStudy (agent0smith):

Why would you find the slope between two points which are on different graphs?

OpenStudy (gottennis121):

But I need to put them in one equation, that's where I'm stuck.

OpenStudy (agent0smith):

That makes no sense.

OpenStudy (s4sensitiveandshy):

then.. how would we find the equation ? there is no other information that we can use...

OpenStudy (agent0smith):

You have two different graphs. Making one equation for them is nonsense.

OpenStudy (gottennis121):

https://www.connexus.com/content/media/1140506-5262015-94221-AM-707560637.pdf That's the portfolio.

OpenStudy (agent0smith):

Take a screenshot.

OpenStudy (gottennis121):

http://screenpresso.com/=EaDZe

OpenStudy (gottennis121):

Maybe the better question is, am I even doing it right?

OpenStudy (agent0smith):

Ah, that is entirely different to the two graphs you posted... what you've done so far doesn't seem useful. You need to make equations that depend on time. Using distance = speed*time

OpenStudy (s4sensitiveandshy):

#3 *write a system of two linear equation*

OpenStudy (gottennis121):

So as far as time goes... I need to base it off time instead?

OpenStudy (agent0smith):

Eg for the cheetah: d = 70t For the rabbit: d = 35t But since the cheetah runs faster, you'll need to give the rabbit a headstart, put him a certain distance ahead. eg. d = 35t + 50, ie the rabbit is getting a 50 mile headstart.

OpenStudy (gottennis121):

Agent0smith had stated the following in a PM: For 3 miles and 1.5 miles you could make the cheetah's equation d = 70t Rabbit's equation: d=35t + 1.5 (which is like he's starting 1.5 miles ahead (Or divide by two once working out the rest of the question). @mathmale I am still a bit stuck.

OpenStudy (gottennis121):

So it'd be rabbit: 1.5 = 35t And cheetah 3.0 =70t ?

umerlodhi (umerlodhi):

Hey lauren i medaled you bye <3

OpenStudy (gottennis121):

Nevermind, I got it. Thanks for your help guys!

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