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calc help
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hi
hi
one question do you go to flvs
yeah why
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i do to!
lol
are you in calculus
\[\frac{d}{dx}[f(3x)]=3f'(3x)\]
nope im only in 5th grade taking 7th and 6th grade math
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how do i take the deriv of [f(3x)
well see ya later
\[g(0.1)=f(3\times 0.1)=f(0.3)\] for starters
g(0.1)=f(.03)? How do I find what f is
congratz sat on 100SS
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i don't know what you mean you don't need "f" you need \(g'(0.1)\) which, by the chain rule, is \[3f'(3x)\]
so i put in .1 into that? so 3f'(.3)?
@ganeshie8
both ways give you the same answer 1) if you take g(0.1) = f(3*0.1) = f(0.3) then g'(0.1) = f'(0.3) =3 2) if you use chain rule for f'(3x) = 3f'(x) , then g(0.1) = 3f'(0.1) =3*1=3
oh, thanks!
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