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Mathematics 12 Online
OpenStudy (anonymous):

calc help

OpenStudy (anonymous):

OpenStudy (anonymous):

hi

OpenStudy (anonymous):

hi

OpenStudy (anonymous):

one question do you go to flvs

OpenStudy (anonymous):

yeah why

OpenStudy (anonymous):

i do to!

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

are you in calculus

satellite73 (satellite73):

\[\frac{d}{dx}[f(3x)]=3f'(3x)\]

OpenStudy (anonymous):

nope im only in 5th grade taking 7th and 6th grade math

OpenStudy (anonymous):

how do i take the deriv of [f(3x)

OpenStudy (anonymous):

well see ya later

satellite73 (satellite73):

\[g(0.1)=f(3\times 0.1)=f(0.3)\] for starters

OpenStudy (anonymous):

g(0.1)=f(.03)? How do I find what f is

OpenStudy (skyvoltage):

congratz sat on 100SS

satellite73 (satellite73):

i don't know what you mean you don't need "f" you need \(g'(0.1)\) which, by the chain rule, is \[3f'(3x)\]

OpenStudy (anonymous):

so i put in .1 into that? so 3f'(.3)?

OpenStudy (anonymous):

@ganeshie8

OpenStudy (loser66):

both ways give you the same answer 1) if you take g(0.1) = f(3*0.1) = f(0.3) then g'(0.1) = f'(0.3) =3 2) if you use chain rule for f'(3x) = 3f'(x) , then g(0.1) = 3f'(0.1) =3*1=3

OpenStudy (anonymous):

oh, thanks!

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