Question

Each of two urns contains green balls and red balls. Urn I contains 8 green balls and 12 red balls. Urn II contains 5 green balls and 8 red balls. If a ball is drawn from each urn, what is P(red and red)?
A. 79/65
B. 24/65
C. 20/30
D. 2/13

Answer 1

U_1 = 12/20 || U_2 = 8/13

The probability of two events happening is their product. After you simplify the fraction, you will find the answer.

Answer 2

The events 'draw a ball from urn I' and 'draw a ball from urn II' are independent. Therefore the probability P(red and red) is the product of the two probabilities:
\[\large P(red\ with\ red)=\frac{12}{20}\times\frac{8}{13}=? \]

Answer 3

one moment

Answer 4

.3?

Answer 5

@Mehek14

Answer 6

HI! Thank god someone is here haha

Answer 7

Heyo! What @kropot72 is quite right and your answer is sort of correct....it would actually be `3.692307...` in which it continues on. Which answer have you chosen?

Answer 8

Yeah I dont know honestly lol

Answer 9

Well we would first multiply the fractions of course...

\(\Huge{\frac{12}{20} \times \frac{8}{13} = \frac{96}{260}}\)

Now we would simplify this....what number would be simplify by?

Factors of 260: 1,2,4,5,10,13,20,26,52,65,130,260
Factors of 96: 1,2,3,4,6,8,12,16,24,32,48,96

The factor we will use is the one they both have in common.

Answer 10

So t would be 2?

Answer 11

Not quite. It would actually be 4 :) So we divide by 4...

\(\Huge{\frac{96}{260} \div \frac{4}{4} = ?}\)

Answer 12

ohhh thats right the last one

Answer 13

1

Answer 14

Last one? Do you mean D?

Answer 15

No the last number as in 4

Answer 16

Ooo ok

Answer 17

So what would it be?

Answer 18

Well we would divide by 4...

\(\Huge{\frac{96 \div 4}{260 \div 4}=?}\)

What did you get?

Answer 19

24/ 65

Answer 20

So the answer is B ^^

Answer 21

Oh awesome thank you can you answer some more?