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Mathematics 21 Online
OpenStudy (jazzy99):

Fan and medal for help. I can't figure this out. I'd really appreciate someone explaining how to get the answer so I can learn and try to solve them on my own. The pic has all the info. http://i67.tinypic.com/2dukpyw.jpg

OpenStudy (anthonyym):

Use pythagorean theorem to write 3 equations, one equation for each triangle. Then you can solve for the variables with the 3 equations since you will have 3 equations and 3 variables.

OpenStudy (legomyego180):

The third triangle is not a right triangle, you cannot use the Pythagorean theorem on non right triangles.

OpenStudy (legomyego180):

Is this for a trig class?

OpenStudy (legomyego180):

Ah nevermind, they are all three right triangles.

OpenStudy (jazzy99):

What would the three equations look like? Why would I need three to get one answer? Will each equation answer be the same? @anyhonyym

OpenStudy (jazzy99):

No, it's just a geometry lesson.

OpenStudy (jazzy99):

@anthonyym

OpenStudy (anthonyym):

Hm I can't view your image anymore

OpenStudy (jazzy99):

Oops, here.

OpenStudy (anthonyym):

There will actually be 3 answers because you need to find the values for 3 variables

OpenStudy (anthonyym):

Are you familiar with the pythagoran theorem? a^2 + b^2 = c^2

OpenStudy (jazzy99):

So I'd need to find y and z in order to find x?

OpenStudy (jazzy99):

I think so yes, but all I have in my material is this example.

OpenStudy (jazzy99):

I think I'm suppose to be finding and using geometric means...

OpenStudy (anthonyym):

Oh I forgot about that... But yes, to solve with the Pythagrean theorem (which equates 3 sides) you will need variable y which you find with variable z. You can go ahead and use those corollary equations.

OpenStudy (jazzy99):

Are the three examples the three equations you were talking about?

OpenStudy (anthonyym):

No, the 3 equations were to be found by using pythagrean theorem on each of the triangles.

OpenStudy (jazzy99):

Okay I used the C-1 and came up with 4/x=x/9, 5/z=z/9 which is 36, 45 then finding the square root is 6, 6.70 ... did I do that right? and should I do C-2 now?

OpenStudy (jazzy99):

C-2 is 4/y = y/5 > 20 > which is then 4.47 with square root. C-3 is Y9=XB which I don't think is right... @anthonyym

OpenStudy (jazzy99):

I used the answer from C-1 which was 6 and it was right. I still don't know how I got the answer though. Like why wasn't it the 6.70, 4.47 or the C-3 option lol

OpenStudy (priyar):

You need to use pythogoras theorem here. Do you know that ? @Jazzy99

OpenStudy (jazzy99):

I didn't know that's what I'm supposed to use. My material just says something about corollaries. a^2 + b^2 = c^2 this is the Pythagoras theorem I know, but I don't know how or which values to plug into it. @priyar

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