Question

AAA TRINOMIALS !! I forgot how They look /.<

Answer 1

perfect... square trinomial?

Answer 2

Oh i though i posted it all
"Which of the following constants can be added to\[ x^2 - x\] to form a perfect square trinomial?"

Answer 3

\((a+b)^2=a^2+2ab+b^2\) so for example \[x^2+14x+49=(x+7)^2\]

Answer 4

ooh different question , and this one is kind of tricky

Answer 5

Yea i forgot how trinomials look >.>

Answer 6

\[x^2-\color{red}1x\] takes two steps

Answer 7

what is half of \(\color{red}1\)

Answer 8

Okay, x(x−1)
*aaa falls*

Answer 9

no dear, what is half of one?

Answer 10

Uhhh i believe it should be .5

Answer 11

a very nice trick

\((a+b)^3=a^3+3a^2b+3ab^2+b^3\)

3(1)/1 = 3
2*3=2 = 3
1(3)/3 = 1

So taking the power of a and then multiplying that by the coefficient on that term and then dividing by what ever term you are in +1 gives the coefficient of the next term.

This is very nice...

Example

(a+b)^5 will look like this without the coefficients

a^5+a^4b+a^3b^2+a^2b^3+ab^4+b^5

Now we find the coefficients

for sure the first one is 1

to find the second we take the power on a in the first term, multiply that my the coefficient on the first term, and divide that by what ever term we are in.

5*1=5 so our second coefficient is 5

now 5*4/2 = 10 so the third is 10

3*10/3 = 10 so the fourth is also 10

2*10/4= 5 so the 5th coefficient is 5

finally 1*5/5 = 1 is the last coefficient