Is heat from radiation same as light ?
why can't we ever have history debates
idk maybe something about the wave lengths are different?
My textbook says, when an electron jumps from higher energy level to a lower energy level, it releases an energy equal to the difference between energy levels; it can release the energy by emitting a photon or by radiating out heat. What does it mean by radiating out heat ?
I agree history debates are more fun
want to have one
Heat from radiation - such as an electric fire - is INFRARED - and there is the term "red hot" ... So, if something is red hot, it is also emitting radiation which you can "see" - provided you are looking in the right direction. The word "light" often refers to red orange yellow green blue indigo violet or the VISIBLE spectrum. If you look at an orange (the fruit), then light from the orange gets into your eye and you can "see" it. "Same as" ? Yes, in the sense that the thing you're talking about is ELECTROMAGNETIC RADIATION. But, infrared electromagnetic radiation is at a different FREQUENCY to, say, blue or X-rays, or MOBILE PHONE radio waves.
well think of it this way, the sun emits three parts of the electromagnetic spectrum. Light, heat and UV radiation. You can see the light, you can feel the heat (they are quite distinct - for example you can feel hot even in the dark and vice versa) and you will feel the UV radiation after long enough.
My specific question is about the difference between a "photon" and "radiated heat" in the context of electron jumps
Are you saying that heat is infrared part of the electromagnetic spectrum ?
When I say "light", I am referring to the entire electromagnetic spectrum. Not just the visible light
CAN you SEE light ? If you could, there'd be so much of it flying around that you wouldn't be able to "see" where you were going ... ??? If light comes from, say, the moon or the sun AND some of it directly enters your eye ("line of sight") then you see the object, by way of the light. But, you probably can't "see" light itself. When you "see" an intense beam - a laser for example - what's happening is that in air, say, some "bits" of the air are deflecting or "scattering" light out of the beam and into your eye.
What you're saying is interesting and is true. But my question not that
My question is this : What's the difference between "photon of electromagnetic radiation" and "heat from radiation" in the context of electron jumps ?
I think it has to do with black body radiation. I'm not sure... Can somebody kindly dumb it down for me ?
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perhaps one could say radiated heat is a statement given in terms of a wave. Photon in terms of a particle
Whooah... For a physics debate this is way off the mark This is not an area of particular expertise for me BUT The electromagnetic spectrum extends over a huge range of wavelenghts . (ANd the sun emits in WAY more than the 3 mentioned above) The spectrum is continuous but we categorise it for ease into loosely defiend bands 'Light' UV Infrared X-Ray Gamma rays Radio waves MIcrowaves are all 'bands' having different wavelenghts The energy of a photon is defined by its wavelength. So when anergy is emitted by an electron change of level it IS a photon, but the wavelenght of that photon depends on the energy released. Therefore it MAY be a visible light OR other wavelengths. Wavelenths in the IR region are detected by humans as 'HEAT' but they are simply the same, but of different energy, to all other wavelengths. (Happy to be corrected here as it is on the fringes of my learning...)
The following is from https://en.wikipedia.org/wiki/Electromagnetic_spectrum Electromagnetic radiation interaction with matter Region of the spectrum Main interactions with matter Radio Collective oscillation of charge carriers in bulk material (plasma oscillation). An example would be the oscillatory travels of the electrons in an antenna. Microwave through far infrared Plasma oscillation, molecular rotation Near infrared Molecular vibration, plasma oscillation (in metals only) Visible Molecular electron excitation (including pigment molecules found in the human retina), plasma oscillations (in metals only) Ultraviolet Excitation of molecular and atomic valence electrons, including ejection of the electrons (photoelectric effect) X-rays Excitation and ejection of core atomic electrons, Compton scattering (for low atomic numbers) Gamma rays Energetic ejection of core electrons in heavy elements, Compton scattering (for all atomic numbers), excitation of atomic nuclei, including dissociation of nuclei High-energy gamma rays Creation of particle-antiparticle pairs. At very high energies a single photon can create a shower of high-energy particles and antiparticles upon interaction with matter.
Cool
Well I have a very simple answer yes they are same..
I don't know but I assume you're talking about excitation and de-excitation of atoms.... perhaps this heat energy is due to "Internal Conversion": https://en.wikipedia.org/wiki/Nuclear_isomer#Decay_processes ? I'm thinking that this "heat" is basically KE since it seems pretty implicit that it's not heat radiation (i.e. from a photon)
@MrNood completely agree, heat transfer by radiation is same as light and all wavelengths are possible. I think that wiki link talks about photon absorption by atoms/molecules/electrons and how it leads to changes in energy levels. I'm still reading it, thank you :) @Bobo-i-bo Are you suggesting that "heat" here refers to vibration of atoms ? The lost energy of electron manifests as vibration of the atom ? (vibrations only because the topic is about solidstate physics)
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@MrNood completely agree, heat transfer by radiation is same as light and all wavelengths are possible. I think that wiki link talks about photon absorption by atoms/molecules/electrons and how it leads to changes in energy levels. I'm still reading it, thank you :) @Bobo-i-bo Are you suggesting that "heat" here refers to vibration of atoms ? The lost energy of electron manifests as an increase in vibration of the atom ? (vibrations only because the topic is about solidstate physics)
Lol, I don't even know what solid state physics is. But yes, it is elementary knowledge to me that heat is often related to temperature which is basically the average KE of molecules/atoms. That was basic High School level maths :P And so I guess it could mean an increase in vibration of the atom. But it's only a "educated" guess from the little I know :P
educated guesses are good enough for now haha turns out it is indeed true, vibrational energies of atoms in a crystal lattice are discrete and can be changed by photon interactions http://physics-animations.com/Physics/Phonons.gif So, for an excited electron, photon emission is not the only way to give off energy in order to reach a lower stable state. I wonder how exactly electron jumps contribute to an increase/decrease in these vibrational energy levels...
The way to look at it is : photons are essentially packets of energy. It shows both particle and wave like nature. The heat radiation is basically the electromagnetic wave that carries this energy. In atomic levels when an electron moves from one shell to another it emits energy which is quantized and this will be a multiple of these discrete packets of energy. The emitted wave is electromagnetic and this explains how it can travel without medium. Radiation is an after effect of of photon emission. Both are not the same.
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"it can release the energy by emitting a photon or by radiating out heat." I think this is just poor wording on the part of the book. ""it can release the energy by emitting a photon" was all that was necessary.
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Radiation is one of three forms of heat transmission. Conduction (moving heat from molecule to molecule) and convection (moving the molecule that have the heat) are the other two. Heat transmission through radiation is the only form that is a form of light, infrared light to be exact. So heat radiation is a form of light.
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