Question

Please help
Simplify:
Sqrt(20/3n^3)

Answer 1

What are you trying to find?

Answer 2

what the simplified version is

Answer 3

I'm not sure that can be simplified. Can you try typing it with the equation editor?

Answer 4

\[\sqrt{20/3n^3}\]

Answer 5

I'm wondering if we can re-write it like this and then simplify

\[\sqrt{\frac{ 20 }{ 3n^{3 }}} = \sqrt{20}*\sqrt{\frac{ 1 }{ 3n^3 }}\]

Answer 6

I get something funny like \[\frac{ 2\sqrt{15n ^{3}} }{ 3n ^{3} }\]

Answer 7

I believe the answer is something like that

Answer 8

oh but that's only if you're required to rationalize, if not it's just 2sqrt(5)/sqrt(3n^3)

Answer 9

how do you get the 15 on the top?

Answer 10

when you factor sqrt(20), it becomes sqrt(4*5), and it can be written as 2sqrt(5).
When you have the sqrt(3n^3) on the bottom, you usually multiply fraction by sqrt(3n^3)/sqrt(3n^3) to get rid of the sqrt on the bottom, so the top is 2sqrt(5)*sqrt(3n^3), and the 5 goes into the sqrt(3n^3), making it sqrt(15n^3)

Also i'm sorry the equation maker thing takes me too long

Answer 11

okay thank you

Answer 12

See the attached PDF for a similar example.

Answer 13

@jim_thompson5910 Do you agree with my answer? Just wondering

Answer 14

Which answer @Erak this one you wrote here?

\[\Large \frac{ 2\sqrt{15n ^{3}} }{ 3n ^{3} }\]

Answer 15

yeah

Answer 16

oh wait I see a way to simplify it more

Answer 17

it's equivalent to the original expression but you can simplify that. So it's not the final answer

Answer 18

yeah, those pesky n^2's. would that be the solution afterwards?

Answer 19

\[\Large \Large \frac{ 2\sqrt{15n ^{3}} }{ 3n ^{3} } = \Large \frac{ 2\sqrt{n^2*15n} }{ 3n ^{3} }\]
\[\Large \Large \frac{ 2\sqrt{15n ^{3}} }{ 3n ^{3} } = \Large \frac{ 2\sqrt{n^2}*\sqrt{15n} }{ 3n ^{3} }\]
I'm sure you know what to do for the rest of the steps