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If the hypotenuse of a right triangle is
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\(2\sqrt{3}\) units long and one of the legs is \(\sqrt{3}\)units long, then how long is the other leg?
For which i got 3
Make use of the pythagorean theorem: \[a^2+b^2=c^2 \] Thereby, by given information we know that \(c=2 \sqrt3\) and let's say that "a" is the leg with the given length, then \(a= \sqrt 3\), then replacing: \[(2\sqrt 3)^2 = (\sqrt 3)^2 +b^2\] Simplifying: \[12=3+b^2\] Now it's a matter of solving for "b".
4
Not correct. \[b^2=12-3\]
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Oh 12 -3.. duhh i forgot it's actually 9
\[\sqrt{9}=?\]
3
Well done! :)
wait that' sall o_o
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lol I helped a little bit XD
yep
Mkay thanks guys cx
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