Which of the following points lies on the circle whose center is at the origin and whose radius is 10?
\[(0,2\sqrt{5})\]
x^2+y^2=r^2 is general eqn of circle with centre (0,0) and radius r.
Use it here.
Okay the formula u man this one? \[r=\sqrt{(x-0)^2+(y-0)^2}\]
If the point satisfies the equation it is on the circle.
*mean
Yep same as yours.
Oh lol mkay Oh so this one is false 100=(\(2\sqrt{5}\))\(^{2}\)+0
Yeah false
Same thing with this one 100=( \(\sqrt{10}\) )\(^{2}+0\)
and the last choice for which i had is WAIT @AravindG IT SHOWS FALSEE ALSO 100=(\(5\sqrt{5}\))\(^{2}\)+\(\ (5\sqrt{5})^2\)
O.mg. so all of them are false.. how's that possible >.>
what are the options?
Mkay A. (√10, 0) B. (0, 2√5) C. (5√2, 5√2)
option C is correct
you made a typo in your solution
Oh i jsut solved it.. and it doesn't mathces..
you took \[\large \bf 5\sqrt{5}~instead~of~5\sqrt{2}\]
Oh shoot yea i took 5 ooh my bad xP
its okay !
geogebra says that point C is on the curve. So you can use a visual tool like a graphing calculator to check
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