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Mathematics 22 Online
MsBrains (ms-brains):

http://prntscr.com/b5eepn Correct?

OpenStudy (jadedry):

It's incorrect., unfortunately! Would you agree the subtraction of the two fractions = \[\frac{ 4-n^2 }{ (2-n)(n-2) }\]

OpenStudy (jadedry):

Try simplifying from there and see what answer you get.

jimthompson5910 (jim_thompson5910):

I'm not sure why you think it's incorrect @Jadedry

jimthompson5910 (jim_thompson5910):

\[\Large \frac{n}{n-2} - \frac{2}{2-n}\] \[\Large \frac{n}{n-2} - \frac{2}{-n+2}\] \[\Large \frac{n}{n-2} - \frac{2}{-1(n-2)}\] \[\Large \frac{n}{n-2} + \frac{2}{n-2}\] \[\Large \frac{n+2}{n-2}\] --------------------------------------- So \[\Large \frac{n}{n-2} - \frac{2}{2-n}\] simplifies to \[\Large \frac{n+2}{n-2}\]

jimthompson5910 (jim_thompson5910):

oh my bad, I misread what @Ms-Brains chose

OpenStudy (jadedry):

That is correct, but she picked the third option!

OpenStudy (jadedry):

Thank you for the comprehensive steps however! I'm sure she'll find it more useful than mine haha.

MsBrains (ms-brains):

Thank you both very much. cx

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