When light passes from air into water at an angle of 70. degrees from the normal, what is the angle of refraction? The index of refraction for air is 1.00029 and the index of refraction for water is 1.33.

A.
45 Degrees
B.
44.97 Degrees
C.
35.59 Degrees
D.
36 Degrees
E.
70 Degrees

Question

When light passes from air into water at an angle of 70. degrees from the normal, what is the angle of refraction?  The index of refraction for air is 1.00029 and the index of refraction for water is 1.33.

A. 	
45 Degrees
	B. 	
44.97 Degrees
	C. 	
35.59 Degrees
	D. 	
36 Degrees
	E. 	
70 Degrees

ganeshie8 · Answer

Heyy

kendellfawn · Answer

Hello

ganeshie8 · Answer

Do you know Snell's law ?

kendellfawn · Answer

I know that it has something to do with angle of incidence and angle of refraction.

kendellfawn · Answer

But that's about it. It's part of my make up work for school and I wasn't there to learn about this.

ganeshie8 · Answer

https://www.math.ubc.ca/~cass/courses/m309-01a/chu/Fundamentals/snell01.gif

kendellfawn · Answer

How do I account for the refraction index?

ganeshie8 · Answer

1.0029*sin(70) =  1.33*sin(x)

ganeshie8 · Answer

http://m.wolframalpha.com/input/?i=arcsin%281.00029*sin%2870%29%2F1.33%29&x=0&y=0

kendellfawn · Answer

@ganeshie8
In an experiment, you observe that an unknown substance refracts light at a greater angle than water with the same angle of incidence.  You can conclude the following:
 (1 point)
	A. 	
Unknown has a greater index of refraction than water
	B. 	
Unknown has a lesser index of refraction than water
	C. 	
No conclusion can be drawn
	D. 	
The scientists made a mistake and should double check their work

mjdennis · Answer

Look back over the beginning problem that @ganeshie8 helped you solve.  You have the tools you need to set up a thought experiment in the Snell's law formula like this:
1.0029*sin(70) = (unknown index of refraction)*sin(your answer from beginning problem)

It would be nice if you entered a new question here on OS.