There are three colors: red, green, blue. She places a single row of 8 colors. Each color is equally likely to be picked. Find the probability that there are no tiles of the same color next to each other.
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Is this reasoning correct? For first color she can pick anything. So probability for first tile is 1 For 2nd till eighth she can only pick two remaining colors. So probability for all other is 2/3 So the probability is (2/3)^7??
Looks okay to me
Okay
You could also count the number of wsys
*ways
Is this correct if I just refer to arrangements 3x 2^7
How many 8 letter words can be formed using 3 different letters ?
Yes you have it!
8P3?
Why is 8P3 not correct?
No It is 3^8
OHH 8P3 would be correct if repetition is not allowed right?
Each space has 3 colors to choose from
Yes
@ganeshie8 Can you also tell me how to infer the number of arrangements using the probability of occurence of something?
Like there was a question which concerned with the word AMAZED. They asked how many arrangements will be there in which e will be between the 2 A's. They answer was somehow to infer that in almost 1 in 3 case e will be between A. And then they multiplied it with the total permutations.
The problem is how did they know in 1 in 3 cases e will be between A?
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